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horrorfan [7]
3 years ago
6

How do you find the constant rate of change and the Y-intercept of line a, b, and c?

Mathematics
1 answer:
KonstantinChe [14]3 years ago
6 0
So you would use the equation y=mx+b
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A local museum had a total of 38,627 vsitors last year. The museum was open everyday except for four holidays. On average how ma
sweet-ann [11.9K]

38,627/361 = 107.

107 people visit the museum every day according to the information given.

8 0
3 years ago
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Determine whether AB ← → and CD ← → − are parallel, perpendicular, or neither. A(-6, 2), B(−3, -4), C(1, -3), D(3, 4)
guapka [62]
Neither they connect but don’t make a 90 degree angle

6 0
2 years ago
James folds a piece of paper in half several times,each time unfolding the paper to count how many equal parts he sees. After fo
Snezhnost [94]

Answer:

There will be total 2048 parts of the given paper if James if able to fold the paper eleven times.

The needed function is y = 2 ^n

Step-by-step explanation:

Let us assume the piece of paper James decides to fold is a SQUARE.

Now, let us assume:

n : the number of times the paper is folded.

y : The number of parts obtained after folds.

Now, if the paper if folded ONCE ⇒  n = 1

Also, when the pap er is folded once, the parts obtained are TWO equal parts.

⇒  for n = 1 , y = 2       ..... (1)

Similarly, if the paper if folded TWICE  ⇒  n = 2

Also, when the paper is folded twice, the parts obtained are FOUR equal parts.

⇒  for n = 2 , y = 4       ..... (2)

⇒y  = 2^2  =  2^n

Continuing the same way, if the paper is folded SEVEN times  ⇒  n = 7

So, y = 2^ n = 2^7 = 128

⇒  There are total 128 equal parts.

Lastly,  if the paper is folded ELEVEN  times  ⇒  n = 11

So, y = 2^ n = 2^{11} = 2048

⇒  There are total 2048 equal parts.

Hence, there will be total 2048 parts of the given paper if James if able to fold the paper eleven times.

And the needed function is y = 2 ^n

8 0
3 years ago
What is the volume of this cylinder? Use 3.14 and round your answer to the nearest hundredth. the diameter is 16 cm and the heig
Zanzabum

Find the area of the base A=64\pi.

Multiply area of the base by height to get volume

V=20\cdot64\pi=4021.24

Hope this helps.

5 0
3 years ago
Read 2 more answers
Derivative of y=cos²x-sin²x
Leona [35]
One thing to bear in mind with trigonometric expressions is that, the exponent location is next to the function name, instead of the whole expression, though it applies to the whole thing, namely cos²(x), is really [ cos(x) ]², and that matters for using the chain rule.

\bf y=cos^2(x)-sin^2(x)\implies y=[cos(x)]^2-[sin(x)]^2
\\\\\\
\cfrac{dy}{dx}=\stackrel{chain~rule}{2cos(x)\cdot -sin(x)}~~-~~\stackrel{chain~rule}{2sin(x)\cdot cos(x)}
\\\\\\
\cfrac{dy}{dx}=-2cos(x)sin(x)-2cos(x)sin(x)
\\\\\\
\cfrac{dy}{dx}=-4cos(x)sin(x)
8 0
3 years ago
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