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3 years ago

How do you find the constant rate of change and the Y-intercept of line a, b, and c?

Mathematics

1 answer:

KonstantinChe [14]3 years ago

6 0

So you would use the equation y=mx+b

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Example 2: Combining Use of the Multiplication and Addition Rules

bulgar [2K]

Answer:

The probability of getting 6's on both cubes is $\frac{1}{36}$ .

The probability that the total score is at least 11 is $\frac{1}{12}$ .

Step-by-step explanation:

Consider the provided information.

A red cube has faces labeled 1 through 6, and a blue cube has faces labeled in the same way.

Part (A) Both cubes show 6’s.

Probability of getting 6 on red cube is $\frac{1}{6}$

Probability of getting 6 on blue cube is $\frac{1}{6}$

Thus, the probability of getting 6's on both cubes is:

$P(\text{Both 6's})=\frac{1}{6}\times\frac{1}{6}=\frac{1}{36}$

Hence, the probability of getting 6's on both cubes is $\frac{1}{36}$ .

Part (B) The total score is at least 11.

The possible number of outcomes in which total score is at least 11 is:

Red shows 6 and Blue shows 5.

Blue shows 6 and Red shows 5.

Blue shows 6 and Red shows 6.

Thus, the probability of total score is at least 11.

$P(\text{Total is at least 11})=\frac{1}{6}\times\frac{1}{6}+\frac{1}{6}\times\frac{1}{6}+\frac{1}{6}\times\frac{1}{6}\\P(\text{Total is at least 11})=\frac{1}{12}$

Hence, the probability that the total score is at least 11 is $\frac{1}{12}$ .

3 0

3 years ago

Enter the unknown number for n. 12.66 − n = 7.64 Brainliest..........

Gemiola [76]

Answer:

Step-by-step explanation:

12.66-n=7.64

12.66-7.64=n

5.02=n

5 0

3 years ago

Read 2 more answers

What is the fractional equivalent of 0.2323? 23/99 23/999 2/9

morpeh [17]

It should be 23/99

23/99= 0.232323...
23/999= 0.023023023....
2/9= 0.222222....

Final answer: 23/99

7 0

3 years ago

M∠PQS = 87°, and m∠SQR = 33°. what is m∠PQR.

defon

Given:
∠PQS = 87°, and m∠SQR = 33° find m∠PQR .

m∠PQR
= m∠PQS + m∠SQR
= 87° + 33°
= 120°

7 0

3 years ago

Help please & thank you so much

Alex787 [66]

D. probably im not that smart though but I hope this helps

5 0

3 years ago