Ii.First ,expand: 5(x-2)=32
5x-10=32
bring 10 to the other side (add it to 32)
5x=42
divide both sides by 5 to get x
x=42/5
x=8.4
iii.Expand 5+2(x+3)=21
5+2x+6=21
bring 5 and 6 to the other side
2x=21-5-6
2x=10 divide both sides by 2
x=5
Answer:
IDK MABY U
Step-by-step explanation:
Answer:
for an infinite geometric series the formula for the sum of the infinite geometric series when the common ratio is less than one is given by
= 
= 144.
Step-by-step explanation:
i) from the given series we can see that the first term is 
= 120.
ii) let the common ratio be r.
iii) the second term is 20 = 120 × r
therefore r = 20 ÷ 120 = 
iv) the third term is 
= 20 × r
therefore r = 
÷ 20 =
v) for an infinite geometric series the formula for the sum of the infinite geometric series when the common ratio is less than one is given by
= = 144.
Hello!
To solve this we will use substitutions and a system of equations where L= length and w=width.
128=2L+2w
L=8+3w
We will substitute L with what it says it equals in the second equation.
128=2(8+3w)+2w
128=16+8w
112=8w
14=w
Now we find the length in the second equation.
L=8+42
L=50
Now we check the length and width in the original equation.
128=100+28
128=128
The length is 50 cm, and the width is 14.
Hope this helps!
