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LuckyWell [14K]
3 years ago
10

Calculate the molarity of a solution obtained dissolving 10.0 g of cobalt(Ⅱ) bromide hexahydrate in enough water to make 450 mL

of solution 7.64 × 10-2 6.80 × 10-2 0.102 M 8.55 × 10-2 6.80 × 10-5
Chemistry
1 answer:
katovenus [111]3 years ago
8 0

Answer:

The molarity of this solution is 6.8 * 10^-2 M

Explanation:

<u>Step 1:</u> Data given

Mass of CoBr*6H2O = 10.0 grams

Molar mass of cobalt(Ⅱ) bromide hexahydrate =

Volume of the solution = 450 mL = 0.450 L

<u>Step 2:</u> Calculate moles of cobalt(Ⅱ) bromide hexahydrate

Number of moles = Mass / molar mass

Number of moles = 10.0 grams / 326.85 g/mol

Number of moles = 0.0306 moles

<u>Step 3:</u> Calculate molarity of the solution

Molarity = number of moles / volume

Molarity = 0.0306 moles / 0.450L

Molarity = 0.068 M = 6.8 * 10^-2 M

The molarity of this solution is 6.8 * 10^-2 M

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Answer:

Please, see attached two figures:

  • The first figure shows the solutility curves for several soluts in water, which is needed to answer the question.

  • The second figure shows the reading of the solutiblity of NH₄Cl at a temperature of 60°C.

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Explanation:

The red  arrow on the second attachement shows how you must go vertically from the temperature of 60ºC on the horizontal axis, up to intersecting curve for the <em>solubility</em> of <em>NH₄Cl.</em>

From there, you must move horizontally to the left (green arrow) to reach the vertical axis and read the solubility: the reading is about in the middle of the marks for 50 and 60 grams of solute per 100 grams of water: that is 55 grams of grams of solute per 100 grams of water.

Assuming density 1.0 g/mol for water, 10 mL of water is:

            10mL\times 1.0g/mL=10g

Thus, the solutibily is:

      10gWater\times 55gNH_4Cl/100gWater=5.5gNH_4Cl

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The question is improperly formatted.

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