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3 years ago

What is the volume of a 25 g object with a density of 9.1 g/mL? please help me

Chemistry

1 answer:

Westkost [7]3 years ago

4 0

Answer:

<h3>The answer is 2.75 mL</h3>

Explanation:

The volume of a substance when given the density and mass can be found by using the formula

$volume = \frac{mass}{density} \\$

From the question we have

$volume = \frac{25}{9.1} \\ = 2.747252...$

We have the final answer as

Hope this helps you

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How many CO2 molecules in 0.0189 mol of CO2?

Blizzard [7]

Answer:

option C is correct = 1.14 × 10²² molecules of CO₂

Explanation:

Given data:

Number of moles of CO₂ = 0.0189 mol

Number of molecules = ?

Solution:

The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.

The number 6.022 × 10²³ is called Avogadro number.

For example,

18 g of water = 1 mole = 6.022 × 10²³ molecules of water

For given question:

1 mole of CO₂ = 6.022 × 10²³ molecules of CO₂

0.0189 mol of CO₂ × 6.022 × 10²³ molecules of CO₂ / 1mol

1.14 × 10²² molecules of CO₂

Thus, option C is correct.

4 0

3 years ago

Fritz-Haber process

maks197457 [2]

Answer:

5×10⁵ L of ammonia (NH3)

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

N2 + 3H2 —> 2NH3

From the balanced equation above, we can say that:

3 L of H2 reacted to produce 2 L of NH3.

Finally, we shall determine the volume of ammonia (NH3) produced by the reaction of 7.5×10⁵ L of H2. This can be obtained as illustrated below:

From the balanced equation above,

3 L of H2 reacted to produce 2 L of NH3.

Therefore, 7.5×10⁵ L of H2 will react to produce = (7.5×10⁵ × 2)/3 = 5×10⁵ L of NH3.

Thus, 5×10⁵ L of ammonia (NH3) is produced from the reaction.

6 0

3 years ago

If the sample has a total mass of 5.76 g and contains 1.79 g k, what are the percentages of kbr and ki in the sample by mass

Luden [163]

The percentages of KBr and KI in the sample by mass is 80.68 and 19.32 % respectively.

<h3>What is Molar Mass ?</h3>

Molar mass is defined as the mass contained in 1 mole of sample.

It is given that

the sample has a total mass of 5.76 g contains KBr and KI

and contains 1.79 gm of K is present

what is the percentage of KBr and KI in the sample

Molecular weight of K = 39

Molecular weight of Br = 79.9

Molecular weight of I = 126.9

In KBr the mass percentage of K is 39/(39+79.9) = 32.89%

In KI the mass percentage of K is 39/(39+126.9) = 23.5%

Let the mass of KBr present in the sample is x

K will be 0.3289 x

and let the mass of KI present be y

K will be 0.235y

x +y =5.76

0.3289x+0.235y = 1.79

0.0939y = 0.1045

y = 1.1125 gm

x = 5.76-1.1125

x = 4.6475 gm

% of KBr = (4.6475/5.76 )*100 = 80.68 %

% of KI = (1.1125/5.76) *100 = 19.32%

To know more about Molar Mass

brainly.com/question/12127540

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8 0

2 years ago

On a graph showing distance versus time, a horizontal line represents an object that is

riadik2000 [5.3K]

Answer:

the anwser is; B: increasing its speed

5 0

3 years ago

How many grams of NaCl are needed to prepare 60 g of a 6.0% solution?

AlekseyPX

Answer:

3.6 grams of NaCl are needed

Explanation:

Percent solution are solutions whose concentrations are expressed in percentages. The amount(either weight or volume) of a solute is expressed as a percentage of the total weight or volume of solution. Percent solutions can either be expressed as weight/volume % (wt/vol % or w/v %), weight/weight % (wt/wt % or w/w %), or volume/volume % (vol/vol % or v/v %).

A 6.0% wt/wt % solution contains 6 g of solute in 100 g of solution

Therefore, a 100 g solution contains 6.0 g of solute.

60 g of 6.0% solution will contain 60 g solution * 6.0 g solute/ 100 g solution

Mass of NaCl present = 3.6 g of NaCl

3 0

3 years ago

What is the volume of a 25 g object with a density of 9.1 g/mL? please help me​

What is the volume of a 25 g object with a density of 9.1 g/mL? please help me