Answer:
Final molarity of iodide ion C(I-) = 0.0143M
Explanation:
n = (m(FeI(2)))/(M(FeI(2))
Molar mass of FeI(3) = 55.85+(127 x 2) = 309.85g/mol
So n = 0.981/309.85 = 0.0031 mol
V(solution) = 150mL = 0.15L
C(AgNO3) = 35mM = 0.035M = 0.035m/L
n(AgNO3) = C(AgNO3) x V(solution)
= 0.035 x 0.15 = 0.00525 mol
(AgNO3) + FeI(3) = AgI(3) + FeNO3
So, n(FeI(3)) excess = 0.00525 - 0.0031 = 0.00215mol
C(I-) = C(FeI(3)) = [n(FeI(3)) excess]/ [V(solution)] = 0.00215/0.15 = 0.0143mol/L or 0.0143M
Answer:
Explanation:
Translated:
Calculate the amount of sugar (C12 H22 O11) in the morning tea if a teaspoon contains 5g of sugar?
Given parameters
Mass of sugar = 5g
Unknown:
Amount of the sugar =?
Solution:
A mole is the amount of substance that contains avogadro's number of particles i.e 6.02 x 10²³
Therefore, to find the number of moles contained in the teaspoon of sugar we use the expression below:
Number of moles = 
Molar mass of C₁₂H₂₂O₁₁ = (12x12) + (1x22) + (16x11) = 342g/mol
Number of moles =
= 0.015mol of sugar
or 0.015 x 6.02 x 10²³, 8.8x10²¹atoms of sugar
Answer:
Explanation:
From the information given:
Mass of carbon tetrachloride = 5 kg
Pressure = 1 bar
The given density for carbon tetrachloride = 1590 kg/m³
The specific heat of carbon tetrachloride = 0.84 kJ/kg K
From the composition, the initial volume of carbon tetrachloride will be:
= 0.0031 m³
Suppose
is independent of temperature while pressure is constant;
Then:
The change in volume can be expressed as:





However; the workdone = -PdV

W = - 7.6 J
The heat energy Q = Δ h


Q = 84 kJ
The internal energy is calculated by using the 1st law of thermodynamics; which can be expressed as;
ΔU = ΔQ + W
ΔU = 84 kJ + ( -7.6 × 10⁻³ kJ)
ΔU = 83.992 kJ
Each isotope has a unique rate of decay, making them suitable for determining the dates of ancient artifacts. The answer is "rate of decay of the isotope."