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Crazy boy [7]
3 years ago
7

The amount of radioactive element remaining, r, in a 100mg sample after d days is represented using the equation r=100(1/2) d/5.

What is the daily percent of decrease
Mathematics
1 answer:
Ludmilka [50]3 years ago
4 0

Answer:

   12.94%

Step-by-step explanation:

r = 100(1/2)^(d/5) = 100((1/2)^(1/5))^d ≈ 100(.87055)^d

The daily decrease is 1 - 0.87055 = 0.12944 ≈ 12.94%

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Simplify -3x+ 5 (3/5x -2 1/5)
Over [174]

Answer:

Step-by-step explanation:

-3x+ 5 (3/5x -2 1/5)

= -3x+ 5 (3/5x - 11/5)

Opening bracket

= -3x+ 3x - 11

= - 11

4 0
3 years ago
How are y'all doing? I'm bored :/<br> Also, good morning
Arturiano [62]
Amazing i hope you have a spectacular day
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2 years ago
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What is the exponential growth for <br><br> 3.821 x (0.54)^2-10
Elan Coil [88]
3.821(0.542)−10=(3.821)(0.2916)−10=1.114204−10=−8.885796

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7 0
3 years ago
⦁ Suppose that the number of bacteria in a dish increases by 50% every four hours. there are 64 bacteria initially. write a func
natta225 [31]
Starting with N = N₀·(1+r)^(t/4)
where N is the number of bacteria at t hours, r is the growth rate, and N₀ is the initial number of bacteria
N₀ = 64
r = 50% = 0.5
So the formula is:
N = 64 · (1+0.5)^(t/4)
N = 64·(1.5)^(t/4)

So after 100 hours,
N = 64 · (1.5)²⁵ = 1.6×10⁶
There are 1.6×10⁶ bacteria at 100 hours.

8 0
3 years ago
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The coordinates of the vertices of triangle ABC are A(3,6), B(6, 3), and C(9, 9). If triangle ABC Is dilated by 1/3x and 1/3y to
katovenus [111]

Answer:

A' =  (1,2)

B'=(2,1)

C' =(3,3)

Step-by-step explanation:

Given

A = (3,6)

B = (6,3)

C = (9,9)

Scale = \frac{1}{3}

Required

Determine the vertices of ABC

If truly the question asks for the vertices of ABC, then the vertices are:

A = (3,6)   B = (6,3)   C = (9,9)

However, I'm quite sure that's not the requirement of the question. So, I'll solve for A'B'C'

To do this, we simply multiply the vertices of ABC by the scale of dilation.

(A'B'C') = Scale\ Factor * (ABC)

A' = \frac{1}{3} * A

A' = \frac{1}{3} * (3,6)

A' =  (\frac{3}{3},\frac{6}{3})

A' =  (1,2)

B' = \frac{1}{3} * B

B' = \frac{1}{3} * (6,3)

B' = (\frac{6}{3},\frac{3}{3})

B'=(2,1)

C' = \frac{1}{3} * C

C' = \frac{1}{3} * (9,9)

C' = (\frac{9}{3},\frac{9}{3})

C' =(3,3)

6 0
2 years ago
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