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natulia [17]
3 years ago
12

Sylvia is twice as old as her brother. Find their ages now if in seven years her brother will be what her age was last year.

Mathematics
1 answer:
igomit [66]3 years ago
6 0

Answer:

Sylvia=16

brother=8

Step-by-step explanation:

8+7=15

16-1=15

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3 years ago
Express 9 m in terms of cm, μm, and nm. Use proper scientific notation in your answers.
devlian [24]

Answer:

9\times10^2cm

9\times10^6 \mu m

9\times10^9nm

Step-by-step explanation:

1 m = 100 cm

9 m = 100cm * 9 = 900 cm or 9\times10^2cm

1 m = 10^6 \mu m

9 m = 9\times10^6 \mu m

1 m = 10^9 nm

9 m = 9\times10^9 nm  

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3 years ago
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stellarik [79]

Answer:

so 80 plus 20 is a 100

Step-by-step explanation:

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3 years ago
What is the lateral area of a regular square pyramid if the base edges are of length 24 and perpendicular height is 5?
iren2701 [21]

Answer:

The lateral area is 624 unit²

Step-by-step explanation:

* Lets explain how to solve the problem

- The regular square pyramid has a square base and four congruent

 triangles

- The slant height of it = \sqrt{(\frac{1}{2}b)^{2}+h^{2}}, where

  b is the length of its base and h is the perpendicular height

- Its lateral area = \frac{1}{2}.p.l, p is the perimeter of the base

 and l is the slant height

* Lets solve the problem

∵ The base of the pyramid is a square with side length 24 units

∵ Its perpendicular height is 5 units

∵ The slant height (l) = \sqrt{(\frac{1}{2}b)^{2}+h^{2}}

∴ l = The slant height of it = \sqrt{(\frac{1}{2}.24)^{2}+5^{2}}

∴ l = \sqrt{(12)^{2}+25}=\sqrt{144+25}=\sqrt{169}=13

∴ l = 13 units

∵ Perimeter of the square = b × 4

∴ The perimeter of the base (p) = 24 × 4 = 96 units

∵ The lateral area = \frac{1}{2}.p.l

∴ The lateral area = \frac{1}{2}.(96).(13)

∴ The lateral area = 624 unit²

* The lateral area is 624 unit²

4 0
3 years ago
A common inhabitant of human intestines is the bacterium Escherichia coli. A cell of this bacterium in a nutrient-broth medium d
qwelly [4]

Answer:

Step-by-step explanation:

Given that,

Cells are divided into two cell every 20mins, this implies that the half-life is 20mins

Initial population growth is 60cells

Growth rate r?

Population growth is modeled as

P(t) = Po•exp(rt)

Where,

Po is the initial growth at t= 0

Po= 60

P(t) is population at any time t.

Since the population doubles every 20mins(⅓hr)

Then, P(⅓) = 2×60 =120

Then, P(t) = 120cells

So, applying the formula

P(t) = Po•exp(rt)

120 = 60•exp(⅓r)

120/60 = exp(r/3)

2 = exp(r/3)

Take In of both sides

In(2) = r/3

Cross multiply

r = 3In(2)

r = 2.079 /hour

The growth rate is 2.079/hour.

7 0
3 years ago
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