Answer:
Answer explained below
Explanation:
I have given two approaches in implementing the solution.
1. Using the for loop, in which you have to iterate over all the elements in list 1 and check in list 2
2. Use the set intersection method. As intersection will give u the common elements. And we can get there length by using len method.
I have added the code along with the snapshot and inline comment for the ease of you to understand. Please check the methods below. You can use either of them.
METHOD-1:
********** CODE *****************
def matches(tickets,winner):
tickets = set(tickets)
winner = set(winner)
counter = 0 #To Count the common elements
for i in tickets: # Iterate over all the elements in tickets.
if i in winner: # Check the element in the winner list
counter = counter+1
return counter
METHOD -2:
********** CODE ********************
def matches(tickets, winner):
tickets = set(tickets)
winner = set(winner)
return len(tickets.intersection(winner))
<u>Answer:</u>
<em>int fNumber,scndNumber = -1, </em>
<em>dup = 0;
</em>
<em>do {
</em>
<em>cin >> fNumber;
</em>
<em>if ( scndNumber == -1) {
</em>
<em>scndNumber = fNumber;
</em>
<em>}
</em>
<em>else {
</em>
<em>if ( scndNumber == fNumber )
</em>
<em>duplicates++;
</em>
<em>else
</em>
<em>scndNumber = fNumber;
</em>
<em>}
</em>
<em>} while(fNumber > 0 ); </em>
<em>cout << dup;
</em>
<u>Explanation:</u>
Here three variables are declared to hold the first number which is used obtain all the inputs given by the user, second number to hold the value of <em>last encountered number and “dup” variable to count the number of duplicate values.</em>
<em>“Do-while”</em> loop help us to get the input check whether it is same as previous input if yes then it <em>adds to the duplicate</em> value otherwise the new previous value if stored.
Answer:
def str_analysis(s):
if s.isdigit():
s = int(s)
if s > 99:
message = str(s) + " is a pretty big number"
else:
message = str(s) + " is a smaller number than expected"
elif s.isalpha():
message = s + " is all alphabetical characters!"
else:
message = "There are multiple character types"
return message;
s = input("enter word or integer: ")
while s != "":
print(str_analysis(s))
s = input("enter word or integer: ")
Explanation:
- Check if the string is digit, alphabetical, or mixed inside the function
- Ask the user for the input
- Call and print the result of the <em>str_analysis</em> function inside the while loop
- Keep asking for the input until the given string is empty
Answer:
The python code is attached
Explanation:
- I defined a function called Fullname
- The function accepts 2 parameters first and last
- last[0] gives the first letter of the last variable
- last[0].upper() modifies the first letter as upper letter
- same applied to variable first
- + sign concatenates strings and variables to the variable name
- the function returns the variable name
