Answer:
0.30
Step-by-step explanation:
Probability of stopping at first signal = 0.36 ;
P(stop 1) = P(x) = 0.36
Probability of stopping at second signal = 0.54;
P(stop 2) = P(y) = 0.54
Probability of stopping at atleast one of the two signals:
P(x U y) = 0.6
Stopping at both signals :
P(xny) = p(x) + p(y) - p(xUy)
P(xny) = 0.36 + 0.54 - 0.6
P(xny) = 0.3
Stopping at x but not y
P(x n y') = P(x) - P(xny) = 0.36 - 0.3 = 0.06
Stopping at y but not x
P(y n x') = P(y) - P(xny) = 0.54 - 0.3 = 0.24
Probability of stopping at exactly 1 signal :
P(x n y') or P(y n x') = 0.06 + 0.24 = 0.30
Answer:
find where they intersect on the graph or find each line's individual equation and set them equivalent to eachother. x=2
6 1/4 mark bainliest plzzz
Answer:
(12x - 6)/5
Step-by-step explanation:
6(2x-1)/5 => (12x - 6)/5 because of the distributive property.
You cannot simplify farther after you reach (12x - 6)/5.
Answer:
what the h3ll type of question is this ?-
Step-by-step explanation:
your never gonna get one because you dont have any so the probability is 0%.
