Answer:
Margin of Error = 5.4088 ;
Confidence interval = (30.1 ; 40.9)
Interval estimate are almost the same
Step-by-step explanation:
Given that :
Population standard deviation, σ = 9.3
Sample size, n = 8
Xbar = 35.5
Confidence level = 90%
The confidence interval:
Xbar ± Margin of error
Margin of Error = Zcritical * σ/sqrt(n)
Zcritical at 90% = 1.645
Margin of Error = 1.645 * 9.3/sqrt(8) = 5.4088
Confidence interval :
Xbar ± Margin of error
35.5 ± 5.4088
Lower boundary = (35.5 - 5.4088) = 30.0912 = 30.1
Upper boundary = (35.5 + 5.4088) = 40.9088 = 40.9
(30.1 ; 40.9)
T distribution =. (30.5 ; 40.5)
Normal distribution = (30.1, 40.9)
Answer:
either 7 or 8 but, 8 is most likely.
start with the numbers in the set 2,3,4,5,6,7,8
its supposed to be between 2 and 8
the only number that would work is 7 and 8 if you use 7 you get 2 and if you use 8 you get 3
Answer:
5 rides.
Step-by-step explanation:
$28 - $6.50 = $21.50
$21.50 - $4 = $17.5
$17.5 ÷ $3 = 5.83
Answer:
Each person should chip in $0.83
Step-by-step explanation:
Total cost =3000km(66/100)(1.20/L)
=45.46 × 1.20
=$54.55
Cost per person = ($54.55/66)
=$0.83 person
Each person should chip in $0.83
Seven tenths of every mile she goes she runs. So we would multiply 4 by seven tenths and get 2.8 miles. And to find out how many miles she walks, we would multiply 4 by three tenth and get 1.2
hope this helped!!
