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Umnica [9.8K]
2 years ago
12

An engineer is building a device to open and close a door. He's using a 48V power supply and needs 3A present at the door motor

to open it properly. What combination of resistors should he use?
Question 10 options:

A)

Two 6 ohms and a 10 ohm

B)

Four 8 ohms and two 4 ohms

C)

Four 2 ohms

D)

Three 8 ohms
Physics
1 answer:
noname [10]2 years ago
3 0

The combination of resistors should he use will be the two resistors one having resistance 10 ohm and another will be 6 ohms. Option A is correct.

<h3 /><h3>What is resistance?</h3>

Resistance is a type of opposition force due to which the flow of current is reduced in the material or wire. Resistance is the enemy of the flow of current.

The given data in the problem is;

V is the voltage= 48 V

Current,I=3A

R is the resistance

From ohm's law the voltage is found as;

V=IR

R=V/I

R=48 / 3

R = 16 ohm

If two resistors have the resistance 6 ohms and 10 ohm connected in the series the equivalent resistance is;

\rm R_{eq}=10 \ ohm + 6 \ ohm \\\\  R_{eq}= 16 \ ohm

He should combine two resistors, one with a resistance of 10 ohms and the other with a resistance of 6 ohms.

Hence, option A is correct.

To learn more about the resistance refer to the link;

brainly.com/question/20708652

#SPJ1

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A car is strapped to a rocket (combined mass = 661 kg), and its kinetic energy is 66,120 J.
labwork [276]

Answer:

9.4 m/s

Explanation:

According to the work-energy theorem, the work done by external forces on a system is equal to the change in kinetic energy of the system.

Therefore we can write:

W=K_f -K_i

where in this case:

W = -36,733 J is the work done by the parachute (negative because it is opposite to the motion)

K_i = 66,120 J is the initial kinetic energy of the car

K_f is the final kinetic energy

Solving,

K_f = K_i + W=66,120+(-36,733)=29387 J

The final kinetic energy of the car can be written as

K_f = \frac{1}{2}mv^2

where

m = 661 kg is its mass

v is its final speed

Solving for v,

v=\sqrt{\frac{2K_f}{m}}=\sqrt{\frac{2(29,387)}{661}}=9.4 m/s

4 0
4 years ago
A motorist drives south at 24.0 m/s for 3.00 min, then turns west and travels at 25.0 m/s for 2.20 min, and finally travels nort
grigory [225]

Answer:

magnitude m = 5440.26 M

average speed is = 25.05 m/s

average velocity = 14.62 m/s

Explanation:

given data

speed v1 = 24 m/s

time t1 = 3 min = 180 s

speed v2 = 25 m/s

time t2 = 2.2 min = 132 s

speed v3 = 30 m/s

time t3 = 1 min = 60 s

total time = 6.2 min = 372 s

to find out

displacement in m  and average speed and  average velocity

solution

so we find here displacement

displacement = vt    .............1

so

displacement 1 = 24 × 180 =  4220 m south = -4220 j   ..........2

displacement 2 = 25 × 132 = 3300 m west = -3300 i     ...........3

distance 3 = 30 × 60 =  1800 m

displacement   = 1800 cos45 -i + 1800 cos45 j

displacement   = -1272.79 i + 1272.79 j                             .............4

so total displacement D =  equation 2 + equation 3 + equation 4

total displacement D =  -4220 j -3300 i -1272.79 i + 1272.79 j

total displacement D =  -2947.21 j - 4572.79 i

so magnitude m = √(-2947.21)² + (-4572.79)² )

so magnitude m = 5440.26 M

and

average speed is = total distance / time

average speed is = (4220 + 3300+ 1800 ) / 372

average speed is = 25.05 m/s

and

average velocity = total displacement / time

average velocity = 5440.26 / 372

average velocity = 14.62 m/s

7 0
4 years ago
300N effort is applied to lift the load of 900N by using a first class lever. If the distance between the load and fulcrum is 20
Klio2033 [76]

Answer:

Effort=300N

Load=900N

Load distance=20m

Now,

Ed=(L*Ld)/E

Ed=(900*20)/300

Ed=1800/300

Ed=6m

Explanation:

7 0
2 years ago
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The Honda cr-z gets 27 miles per gallon on average. How many co2 were emitted if this Honda was driven 386 miles
Volgvan
4000 miles because I did the math online and showed my work on there
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3 years ago
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vladimir2022 [97]

Answer:

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