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Allushta [10]
3 years ago
14

How can the momentum of an object be changed?

Physics
1 answer:
pickupchik [31]3 years ago
3 0
C. You’re welcome





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Where would the net force acting on a charge placed in a system of like charges be zero?
sweet-ann [11.9K]

Answer:

If an object is electrically neutral it has no net charge becuase it has the same number of protons as it does electrons, which are opposite charges that offset each other. No, that just means that the sum of all its positive and negative amounts of charge equals zero.

5 0
3 years ago
Please help with this question, step by step<br><br>Thank you!
mamaluj [8]

From the calculation, the force constant is 192 N. Also, friction would decrease the extension.

<h3>What is the force constant?</h3>

We know that the force constant can be obtained by the use of the relation;

F = Ke

F = applied force

K = force constant

e = extension

We know from Hooks law that the force applied is directly proportional to the extension.

We can write;

F = mgcosθ

F = 43 Kg * 9.8 m/s^2 * sin31°

F = 217 N

K = 217 N/1.13 m

K = 192 N/m

If there is friction between the incline and the crate, it will stretch less because some work will be lost due to friction causing only some fraction of the elastic potential energy to be converted to kinetic energy.

Learn more about Hooke's law:brainly.com/question/14140269

#SPJ1

7 0
1 year ago
A train moves at a constant velocity of 50 km/h. How far will it move in 0.5 h?
solniwko [45]

Answer:

C.25km

Explanation:

half of 50 is 25.

6 0
3 years ago
Read 2 more answers
Thường ngày an đi bộ từ nhà đến trường mất 15 phút biết quãng đường từ nhà đến trường dài 1.5 km tính vận tốc đi thường ngày của
DedPeter [7]

Answer:

Speed in kilometer/hour = 6 kilometer / hour

Explanation:

Given;

Time taken to cover distance = 15 minute = 15 /60 = 0.25 hour

Distance of school = 1.5 kilometer

Find:

Speed in kilometer/hour

Computation:

Speed in kilometer/hour = Distance / Time

Speed in kilometer/hour = Distance of school / Time taken to cover distance

Speed in kilometer/hour = 1.5 / 0.25

Speed in kilometer/hour = 6 kilometer / hour

7 0
3 years ago
The cable of a crane is lifting a 750 kg girder. The girder increases its speed from 0.25 m/s to 0.75 m/s in a distance of 3.5 m
IgorC [24]

To solve this exercise it is necessary to apply the equations concerning Work, both by general definition and by conservation of energy.

In other words, the work done by an object due to gravity is the equivalent to that defined by the potential energy equations, that is

W= mg\Delta h

Where,

m=mass

g=gravitational acceleration

\Delta h = Change in height

On the other hand we have that the work done by tension is defined by the conservation of kinetic and potential energy, that is to say

W= \Delta KE + \Delta PE

Where,

\Delta KE = Change in Kinetic Energy

\Delta PE =Change in Potential Energy

PART A) As defined by the work done by gravity would be given by,

W = mg\Delta h

W = (750)(9.8)(3.5)

W = 25.725kJ

Therefore the work done by gravity is 25.725kJ

PART B) The work done by the tension applies the energy conservation equation, that is to say

W= \Delta KE + \Delta PE

W = (\frac{1}{2}mv_f^2-\frac{1}{2}mv_i^2)+(mgh_f-mgh_i)

W = \frac{1}{2}m(v_f^2-v_i^2)+mg(h_f-h_i)

Replacing with our values,

W = \frac{1}{2}(750)(0.75^2-0.25^2)+(750)(9.8)(3.5)

W = 25.912kJ

Therefore the work done by tension is 25.9kJ

5 0
3 years ago
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