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Allushta [10]
4 years ago
14

How can the momentum of an object be changed?

Physics
1 answer:
pickupchik [31]4 years ago
3 0
C. You’re welcome





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1. Earth's ozone layer is responsible for absorbing from the sun
ladessa [460]

Answer:

UV light

climate

hydrofluorocarbons or HFCs

pollutants

heat

As sunlight falls on Earth's surface, it heats up the surface. Infrared light is emitted from the surface and is absorbed in the atmosphere, where it is converted to heat. This heat remains trapped in the atmosphere, causing the temperature near the surface to increase.

Explanation:

these are all correct

5 0
3 years ago
Read 2 more answers
A lightning flash releases about 1010J of electrical energy. Part A If all this energy is added to 50 kg of water (the amount of
zavuch27 [327]

Answer:

water is in the vapor state,

Explanation:

We must use calorimetry equations to find the final water temperatures. We assume that all energy is transformed into heat

        E = Q₁ + Q_{L}

Where Q1 is the heat required to bring water from the current temperature to the boiling point

      Q₁ = m c_{e} ( T_{f} -T₀)

      Q₁ = 50 4180 (100 - 37)

      Q₁ = 1.317 10⁷ J

Let's calculate the energy so that all the water changes state

     Q_{L}  = m L

     Q_{L}  = 50 2,256 106

    Q_{L}  = 1,128 10⁸ J

Let's look for the energy needed to convert all the water into steam is

     Qt = Q₁ + Q_{L}  

     Qt = 1.317 107 + 11.28 107

     Qt = 12,597 10⁷ J

Let's calculate how much energy is left to heat the water vapor

     ΔE = E - Qt

     ΔE = 10¹⁰ - 12,597 10⁷

     ΔE = 1000 107 - 12,597 107

     ΔE = 987.4 10⁷ J

With this energy we heat the steam, clear the final temperature

     Q = ΔE = m c_{e} ( T_{f}-To)

    ( T_{f}-T₀) = ΔE / m c_{e}

      T_{f} = T₀ + ΔE / m c_{e}

      T_{f} = 100 + 987.4 10⁷ / (50 1970)

      T_{f} = 100 + 1,002 10⁵

      T_{f} = 1,003 10⁵ ° C

This result indicates that the water is in the vapor state, in realizing at this temperature the water will be dissociated into its hydrogen and oxygen components

4 0
3 years ago
A toy rocket is launched straight up into the air as the rocket rises what happens to the velocity
ollegr [7]
The velocity decreases
hope this helps
8 0
3 years ago
A toy train is pushed forward and released at 2.0m with a speed of 1.0m/s. it rolls at a steady speed for 2.0s, then one wheel b
Mila [183]

Recall that

{v_f}^2-{v_0}^2=2a\Delta x

where

- v_f is the final velocity of the train; 0 in this case, because the train eventually stops

- v_0 is the initial velocity of the train; 1.0 m/s in this case, because this initial velocity refers to velocity it starts with after one of the wheels gets stuck, and the train is initially traveling at a constant speed of 1.0 m/s

- a is the acceleration we want to find

- \Delta x is the change in the train's position; 5.0 m in this case

So we have

-\left(1.0\,\dfrac{\mathrm m}{\mathrm s}\right)^2=2a(5.0\,\mathrm m)

\implies a=-0.10\,\dfrac{\mathrm m}{\mathrm s^2}

4 0
4 years ago
What happens to the force between two charges when each charge is doubled and the distance between them is 1/4 its original
DIA [1.3K]

Answer:

F' = 64 F

Explanation:

The electric force between charges is given by :

F=\dfrac{kq_1q_2}{r^2}

Where

q₁ and q₂ are charges

r is the distance between charges

When  each charge is doubled and the distance between them is 1/4 its original magnitude such that,

q₁' = 2q₁, q₂' = 2q₂ and r' = (r/4)

New force,

F'=\dfrac{kq_1'q_2'}{r'^2}

Apply new values,

F'=\dfrac{k\times 2q_1\times 2q_2}{(\dfrac{r}{4})^2}\\\\=\dfrac{k\times 4q_1q_2}{\dfrac{r^2}{16}}\\\\=64\times \dfrac{kq_1q_2}{r^2}\\\\=64F

So, the new force becomes 64 times the initial force.

7 0
3 years ago
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