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kodGreya [7K]
3 years ago
9

Select the three expressions that are equivalent to 6^{2}6 2 6, squared. a: (6^9/6^8)^2 b: 6 times 6 times 6 times 6 times 6 tim

es 6 times 6 / 6 times 6 times 6 c: 6^4/6^2 d: 6^5 times 6^7/6^10
Mathematics
2 answers:
bearhunter [10]3 years ago
4 0

Answer:

acd

Step-by-step explanation:

Kamila [148]3 years ago
3 0

Question:

Select the three expressions that are equivalent to 6^2:

a: (\frac{6^9}{6^8})^2

b: \frac{6 * 6 * 6 * 6 * 6 * 6 * 6}{6 * 6 * 6 }

c: \frac{6^4}{6^2}

d: \frac{6^5 * 6^7}{6^{10}}

Answer:

a: (\frac{6^9}{6^8})^2

c: \frac{6^4}{6^2}

d: \frac{6^5 * 6^7}{6^{10}}

Step-by-step explanation:

Given

6^2:

Required

Find equivalent expressions

<em>To solve this question; we'll simplify options a to do, one after the other</em>

a: (\frac{6^9}{6^8})^2

From laws of indices;

\frac{a^m}{a^n} = a^{m-n}

This implies that;

(\frac{6^9}{6^8})^2 = (6^{9-8})^2

(\frac{6^9}{6^8})^2 = (6^{1})^2

From laws of indices;

{a^m}^n = a^{m*n} = a^{mn}

This implies that

(\frac{6^9}{6^8})^2 = (6^{1*2})

(\frac{6^9}{6^8})^2 = 6^{2}

Hence,  (\frac{6^9}{6^8})^2 is equivalent to 6^2

b. \frac{6 * 6 * 6 * 6 * 6 * 6 * 6}{6 * 6 * 6 }

From laws of indices;

a^m * a^n = a^{m+n}

This implies that

\frac{6 * 6 * 6 * 6 * 6 * 6 * 6}{6 * 6 * 6 }  = \frac{6^{1+1+1+1+1+1}}{6^{1+1+1}}

\frac{6 * 6 * 6 * 6 * 6 * 6 * 6}{6 * 6 * 6 }  = \frac{6^{6}}{6^{3}}

From laws of indices;

\frac{a^m}{a^n} = a^{m-n}

This implies that

\frac{6 * 6 * 6 * 6 * 6 * 6 * 6}{6 * 6 * 6 }  = 6^{6-3}

\frac{6 * 6 * 6 * 6 * 6 * 6 * 6}{6 * 6 * 6 }  = 6^{3}

Hence; \frac{6 * 6 * 6 * 6 * 6 * 6 * 6}{6 * 6 * 6 } is not equivalent to 6^2

c.  \frac{6^4}{6^2}

From laws of indices;

\frac{a^m}{a^n} = a^{m-n}

This implies that

\frac{6^4}{6^2} = 6^{4-2}

\frac{6^4}{6^2} = 6^{2}

Hence, \frac{6^4}{6^2} is equivalent to 6^2

d.  \frac{6^5 * 6^7}{6^{10}}

From laws of indices;

a^m * a^n = a^{m+n}

This implies that

\frac{6^5 * 6^7}{6^{10}} = \frac{6^{5+7}}{6^{10}}

From laws of indices;

\frac{a^m}{a^n} = a^{m-n}

This implies that

\frac{6^5 * 6^7}{6^{10}} = 6^{5+7-10}

\frac{6^5 * 6^7}{6^{10}} = 6^{2}

Hence, \frac{6^5 * 6^7}{6^{10}} is equivalent to 6^2

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vesna_86 [32]

Answer:

see explanation

Step-by-step explanation:

(a)

Consider the denominator

To obtain 5xy from x , multiply by 5y

Thus numerator is multiplied by 5y, that is

\frac{1}{x} = \frac{5y}{5xy}

(b)

Consider the numerator

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Thus denominator is multiplied by 5b, that is

\frac{ab}{2c} = \frac{5ab^2}{10bc}

3 0
3 years ago
A light aircraft travels 5 miles per hour less than twice the speed of a bus. If the bus can travel 114 miles in the same time i
Rufina [12.5K]
A represents the speed of the aircraft.
b represents the speed of the bus.

a=2b-5
114/b=218/a

Substitution method

114/b=218/(2b-5)

(2b-5)*(114/b)= 218

(228b-570)/b = 218

228b-570= 218b

228b-218b=570

10b= 570

b=57

Plug the value of b into one of the original equations.

a=2(57)-5
a=114-5
a=109

Final answer:
Average speed of plane= 109
Average speed of bus= 57
3 0
3 years ago
WILL GET BRAINLIEST IF EXPLAINED AND CORRECT
Anna007 [38]

Answer:

It is D. (x + 1)^2 + (y - 3)^2 = 16.

Step-by-step explanation:

The general equation of a circle is

(x - h)^2 + (y - k)^2 = r^2  where  the center is (h, k) and the radius is r.

So substituting the given values the required equation is:

(x + 1)^2 + (y - 3)^2 = 4^2.

8 0
3 years ago
Read 2 more answers
Determine the range of the function g of x is equal to negative square root of the quantity x squared plus 16 end quantity
vova2212 [387]

Option A is correct. The range of the function  g(x)=-\sqrt{x^2+16} given above expressed as an interval notation is (–∞, ∞)

Given the function g(x)=-\sqrt{x^2+16}

  • We are to find the range of the function.

  • First, we can see that the value of x² inside the square root will always be a positive value no matter the domain values of x.

  • Since the input value exists on all real numbers, hence<em> the output values will also exist on all real numbers since the </em><em>range</em><em> is dependent on the values of the </em><em>domain.</em>

Hence the range of the function given above expressed as an interval notation is (–∞, ∞)

Learn more here: brainly.com/question/16724504

5 0
2 years ago
The area of max'ss room ,not incleding his closet is 235.675 square feet the area of his closet is 10.45 square feet what area o
enyata [817]

Given :

Area of room excluding closet is , a=235.675\ ft^2 .

Area of closet is , b=10.45\ ft^2 .

To Find :

Area of max's room including the closet .

Solution :

Let , area of max's room including the closet is A .

So , Total area = Area of room excluding closet + Area of closet .

A=a+b\\\\A=(235.675+10.45)\ ft^2\\\\A=246.125\ ft^2

Therefore , area of his room ,including the closet is 246.125 square feet .

Hence , this is the required solution .

5 0
3 years ago
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