1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
alexandr402 [8]
3 years ago
15

Y varies directly with x, and y = 15 when x = 3. What is the value of x when y = 4?

Mathematics
2 answers:
vodka [1.7K]3 years ago
8 0
15/3 = 4/x
5 = 4/x 
so
x = 4/5
soldi70 [24.7K]3 years ago
4 0
The answer would be 1 because 4 times 3 equals 12 and u would add 3 so yeha.
You might be interested in
Please Help me!!! <br><br><br> I know the answer but I don’t understand how to get that answer
worty [1.4K]
-7 ÷ 2 1/2
Okay, so first, put the -7 over one and make 2 1/2 an improper fraction. so now:
-7/1 ÷ 5/2
Then, take the reciprocal of 5/2 and multiply it by -7/1
-7/1 × 5/2
Which would be -35/2
5 0
3 years ago
Question 12<br> Given that Zlis a complement of 22 and mZ2 = 17°, find mZ1?
ivann1987 [24]

Answer: B) 73

Step-by-step explanation:

Complementary angles are 2 angles which add up to 90.

90 - 17 = 73

6 0
3 years ago
The number of newly reported crime cases in a county in New York State is shown in
JulsSmile [24]

Answer:

The linear regression equation that represents  the set of data is:

y=1083.48+23.73x

The predicted number of new cases for 2013 is 1368.

Step-by-step explanation:

The general form of a linear regression is:

y=a+bx

Here,

<em>y</em> = dependent variable

<em>x</em> = independent variable

<em>a</em> = intercept

<em>b</em> = slope

Compute the values of <em>a</em> and <em>b</em> as follows:

\begin{aligned}        a &= \frac{\sum{Y} \cdot \sum{X^2} - \sum{X} \cdot \sum{XY} }{n \cdot \sum{X^2} - \left(\sum{X}\right)^2} =             \frac{ 6857 \cdot 55 - 15 \cdot 17558}{ 6 \cdot 55 - 15^2} \approx 1083.476 \\ \\b &= \frac{ n \cdot \sum{XY} - \sum{X} \cdot \sum{Y}}{n \cdot \sum{X^2} - \left(\sum{X}\right)^2}        = \frac{ 6 \cdot 17558 - 15 \cdot 6857 }{ 6 \cdot 55 - \left( 15 \right)^2} \approx 23.743\end{aligned}

The linear regression equation that represents  the set of data is:

y=1083.48+23.73x

Compute the predicted value of the number of new cases for 2013 (i.e. <em>x</em> = 12) as follows:

y=1083.48+23.73x

  =1083.48+(23.73\times12)\\\\=1083.48+284.76\\\\=1368.24\\\\\approx 1368

Thus, the predicted number of new cases for 2013 is 1368.

8 0
3 years ago
- 5<br> 4<br> =<br> 2x - 3<br> 5x -5
Zinaida [17]

Answer:

x = 49/33

Hope this helps you! Even though there's no explanation... (I'm really bad at explaining, I'm just good at doing...)

3 0
3 years ago
Combine the like terms to make a similar expression 2q+2+9
Ede4ka [16]
Add the 2 and 9 together:
2q+11
8 0
4 years ago
Other questions:
  • 6.04 x 10^-3 as an ordinary number
    7·1 answer
  • There are three separate, equal-size boxes, and inside each box there are four separate small boxes, and inside each of the smal
    13·1 answer
  • Explain how knowing that 5 divided by 8 is 0.625 helps you write the decimal for 4 5/8
    13·1 answer
  • Help me. I don't understand it.
    6·1 answer
  • Point B ∈ AC . If points K, M, N, and P are the midpoints of respectively AB , AC , MC , and NC , identify and write a statement
    5·2 answers
  • A graph shows the relationship between the height of a plant and the number of days. On which axis should the height of the plan
    12·1 answer
  • A politician who is running for the office of mayor of a city with 25,000 registered voters commissions a survey. In the survey,
    9·1 answer
  • Common denominator for 3/4 and 7/6
    15·2 answers
  • Susan goes to an amusement park. The admission price to the park is $5. The cost per ride is $4. The total cost Susan spent in t
    14·1 answer
  • A stack of printer paper is 2 inches thick and contains 500 sheets. estimate the thickness of an individual sheet of the printer
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!