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3 years ago

Y=4.5x+13.45 y=6x-4.55

Mathematics

1 answer:

mafiozo [28]3 years ago

6 0

Step-by-step explanation:

Solve for the first variable in one of the equations, then substitute the result into the other equation.

Point Form:

(

67.45

)

Equation Form:

67.45

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Match the variables.

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Where are the variables?

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3 years ago

If angle 1 = angle 2 and angle 2 = angle 4, what property allows you to state that angle 1 = angle 4

Gnesinka [82]

Answer:

Transitive Property

Step-by-step explanation:

You can use it for example: a = b. b = c. So a = c (Transitive Property).

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4 years ago

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kakasveta [241]

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Step-by-step explanation:

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3 years ago

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The sum of 10 times a number and fifteen is added to 11 times the same number. (how do i make this into a algebraic expression?)

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3 years ago

Your school wants to take out an ad in the paper congratulating the basketball team on a successful season, as shown to the rig

iogann1982 [59]

Answer:

$x_1 =-14.43 in, x_2 = 2.426in$

Since the measurement can't be negative the correct answer for this case would be $x =2.426 in$

Step-by-step explanation:

Let's assume that the figure attached illustrate the situation.

For this case the we know that the original area given by:

$A_i = 7 in *5 in = 35in^2$

And we know that the initial area is a half of the entire area in red $A_i = \frac{A_f}{2}$ , so then:

$A_f = 2 A_ i =2*35 = 70$

And we know that the area for a rectangular pieces is the length multiplied by the width so we have this:

$70 = (x+7) (x+5)$

We multiply both terms using algebra and the distributive property and we got:

$70 =x^2 +12 x +5$

And we can rewrite the expression like this:

$x^2 +12 x -35 = 0$

And we can solve this using the quadratic formula given by:

$x = \frac{-b \pm \sqrt{b^2 -4ac}}{2a}$

Where $a = 1, b =12 and c=-35$ if we replace we got:

$x = \frac{-12 \pm \sqrt{(12)^2 -4(1)(-35)}}{2*1}$

And the two possible solutions are then:

$x_1 =-14.43 in, x_2 = 2.426in$

Since the measurement can't be negative the correct answer for this case would be $x =2.426 in$

3 0

3 years ago