First, determine the circumference (C) of the circle, the equation,
C = 2πr
Substituting the value or the radius,
C = 2π ( 4) = 8π
The arc length is the product of the circumference and the ratio between the subtended angle and 360. The mathematical expression is already,
S = (8π) x (72 / 360) = 0.8π
Thus, the arc is 0.80π.
An interval graph in graphical theory is indeed an undirected graph formed by an interval set just on true line, with a top for every interval as well as an edge between vertex v to intersections. Graph intervals and these graphs are chordal graphs and graphs that are perfect, and the further discussion can be defined as follows:
Given:

![\bold{Interval \ \[-6, 3\]}](https://tex.z-dn.net/?f=%5Cbold%7BInterval%20%5C%20%5C%5B-6%2C%203%5C%5D%7D)
To find:
Domain=?
Solution:
The
is a graphic over the
interval.
A<em><u> graph of the domain</u></em>
is indicated mostly by the <em><u>transformation </u></em>that <em><u>horizontal shifts</u></em> to combat
.

=|x-3|
Therefore, the final answer is "Option (D)".
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The mid-point of FJ is the number right in the middle of FJ. Find the mean of F & J. Add regardless of sign
4 + 6 = 10
10/2 = 5
Add 5 to -4
5 + -4 = 1
H is your midpoint
True. As long as AB and BC are on the same line, AB + BC = AC
hope this helps
Answer:
anxiety
Step-by-step explanation: