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jeka57 [31]
3 years ago
15

I NEED HELP LOOK AT IT WHAT IS IT?????????????

Mathematics
2 answers:
Rainbow [258]3 years ago
7 0

Answer:

B

Step-by-step explanation:

2.15 is bigger than 2.087

gladu [14]3 years ago
5 0

Answer:

2.087 < 2.15

Step-by-step explanation:

ok even as a decimal 2.087 is less than 2.15

2.087 < 2.15

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What is the LCM of 8,15,10
GaryK [48]
The LCM for 8, 15, and 10 is 120.
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3 years ago
The ratio of girls to boys in a class is 3:5 what fraction of the class are girls?
Wewaii [24]

Answer:

Hello!!

If the ratio of girls to boys in a class is 3:5, the fraction of the class that are girls is...

\frac{3}{5}

Hope this helps!!

8 0
3 years ago
If you know the diameter of a circle, which statement describes how to find the AREA?
pentagon [3]

Answer:

c

Step-by-step explanation:

PI times radius squared

6 0
3 years ago
Read 2 more answers
Match the key aspect of a function's graph with its meaning
Aliun [14]

Answer:

y- intercept --> Location on graph where input is zero

f(x) < 0         --> Intervals of the domain where the graph is below the x-axis

x- intercept --> Location on graph where output is zero

f(x) > 0         --> Intervals of the domain where the graph is above the x-axis

Step-by-step explanation:

Y-intercept: The y-intercept is equivalent to the point where x= 0. 'x' is the input variable in an equation, therefore the y-intercept is where the input, or x, is equal to 0.

f(x) <0: Notice the 'lesser than' sign. This means that the value of f(x), or 'y', is less than 0. This means that this area consists of intervals of the domain below the x-axis.

X-intercept: The x-intercept is the location of the graph where y= 0, or the output is equal to 0.

f(x) >0: In this, there is a 'greater than' sign. This means that f(x), or 'y', is greater than 0. Therefore, this consists of intervals of the domain above the x-axis.

8 0
3 years ago
PLEASE HELP
lilavasa [31]

Those two functions just miss each other so there are no real solutions.  Every polynomial with complex coefficients has complex solutions.

2x^2 + 2 = 3x

2x^2 - 3x = -2

2( x^2 - \frac 3 2 x) = -2

x^2 - \frac 3 2 x = -1

x^2- \frac 3 2 x+ (\frac 3 4)^2= -1 + (\frac 3 4 )^2

(x - \frac 3 4)^2 = -\frac 7{16}

x - \frac 3 4 = \pm \sqrt{ -\frac 7{16}}

x = \frac 3 4 \pm \frac i 4 \sqrt{7}

x = \frac 1 4(3 \pm i \sqrt{7})


4 0
3 years ago
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