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Lera25 [3.4K]
3 years ago
9

Help. Solve for n: 4n-3h/13=c

Mathematics
2 answers:
lina2011 [118]3 years ago
8 0
First you need to move that n over im fairly certain 
Georgia [21]3 years ago
5 0

Answer:

The Answer is n = \frac{(c*13)+3h}{4}

Step-by-step explanation:

To solve for n , n needs to be by itself on one side. We do this by doing the <u>opposite operations</u> on each side which will cancel out the operations on the left side leaving n by itself.

(4n-3h)/13=c  ....... First multiply 13 on both sides

4n-3h = c*13  ....... Secondly we add 3h on both sides

4n = (c*13)+3h ...... Lastly we divide 4 on both sides

n = \frac{(c*13)+3h}{4}

After following all the steps we are left with n = \frac{(c*13)+3h}{4} which solves for n.

I hope this answered your question. If you have any more questions feel free to ask away at Brainly.

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A $8,000 principal is invested in two accounts, one earning 1% interest and another earning 6% interest. If the total interest f
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The amount invested in the first account is $1,500 and $6,500 was invested in the second account.

What is simple interest?

Simple interest is determined as the principal multiplied by the interest rate ,then multiplied by the duration of the investment.

The formula for simple interest on an investment is as shown below:

I=PRT

P=principal=$8,000

R=interest rates= 1% and 6%

T=duration of investment=1 year

Let assume that X was invested at 1% and that the remaining of $8000-X is invested at 6%.

Interest on the first account=X*1%*1

Interest on the first account=0.01X

Interest on second account=($8000-X)*6%*1

Interest on second account=480-0.06X

Total interest=0.01X+480-0.06X

Total interest=480-0.05X

Total interest=$405

405=480-0.05X

0.05X=480-405

0.05X=75

X=75/0.05

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Amount invested in the second account=$8000-X

Amount invested in the second account=$8,000-$1,500

Amount invested in the second account=$6,500

Find out more about simple interest on:brainly.com/question/1115815

#SPJ1

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