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3 years ago

Here is a sequence of numbers:

Mathematics

1 answer:

S_A_V [24]3 years ago

3 0

Answer:

Perfect squares

Step-by-step explanation:

Here, we have a list of some numbers and we want to know the name given to these numbers.

Mathematically, these numbers are referred to as perfect squares.

Although all numbers have square roots, not all numbers have integer square root values.

Numbers having integer square root values otherwise known as whole number square root values are referred to as perfect squares.

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8. Carisa is four inches taller than her friend Lily.

zhenek [66]

Answer:

cool

Step-by-step explanation:

3 0

3 years ago

The four partners in a business decide to split the profits of their company in the ratio 2 : 3 : 3 : 5 .

Snowcat [4.5K]

Answer:

$10,000

Step-by-step explanation:

the profit was divided to 2+3+3+5=13 parts

the largest amount of profit

=$26,000×5/13

=$10,000

5 0

3 years ago

The function f(x)=(x-5)^2 +2 is not one-to-one. Identify a restricted domain that makes the function one-to-one, and find the in

Anon25 [30]

We have been given a quadratic function $f(x)=(x-5)^{2} +2$ and we need to restrict the domain such that it becomes a one to one function.

We know that vertex of this quadratic function occurs at (5,2).

Further, we know that range of this function is $[2,\infty)$ .

If we restrict the domain of this function to either $(-\infty,5]$ or $[5,\infty)$ , it will become one to one function.

Let us know find its inverse.

$y=(x-5)^{2}+2$

Upon interchanging x and y, we get:

$x=(y-5)^{2}+2$

Let us now solve this function for y.

$(y-5)^{2}=x-2\\
y-5=\pm \sqrt{x-2}\\
y=5\pm \sqrt{x-2}\\$

Hence, the inverse function would be $f^{-1}(x)=5+\sqrt{x-2}$ if we restrict the domain of original function to $[5,\infty)$ and the inverse function would be $f^{-1}(x)=5-\sqrt{x-2}$ if we restrict the domain to $(-\infty,5]$ .

8 0

3 years ago

23n=2.4 A. 3.6 B. 7.2 C. 1.2 D. 1.6

svp [43]

$\huge\text{Hey there!}$

$\mathsf{23n =2.4}$

$\large\text{DIVIDE 23 to BOTH SIDES}$

$\mathsf{\dfrac{23n}{23}=\dfrac{2.4}{23}}$

$\large\text{Cancel out: }\mathsf{\dfrac{23}{23}}\large\text{ because it gives you 1}$

$\large\text{Keep: }\mathsf{\dfrac{2.4}{23}}\large\text{ because it helps us solve for n}$

$\mathsf{n = \dfrac{2.4}{23}}$

$\mathsd{\dfrac{2.4}{23}= 2.4\div 23\rightarrow \bf 0.104348}$

$\boxed{\boxed{\large\textsf{Answer: \huge n = \bf 0.104348}}}\huge\checkmark$

$\boxed{\textsf{NONE OF THE ABOVE is your ANSWER}}$

$\text{Good luck on your assignment and enjoy your day!}$

~ $\frak{Amphitrite1040:)}$

8 0

2 years ago

Lots of points help me! its math 9th grade

77julia77 [94]

I think the answers would be B) 17

4 0

3 years ago

Read 2 more answers