Describe the graph g

Factor using the x method ( please do not answer without showing work )

muminat

Answer:

$5(x + 10)(10x - 3)$

Step-by-step explanation:

We are factoring

$50x^{2} + 485x - 150$

So:

((2•5^2x^2) + 485x) - 150

Pull like factors :

50x^2 + 485x - 150 = 5 • (10x^2 + 97x - 30)

Factor

10x^2 + 97x - 30

Step-1: Multiply the coefficient of the first term by the constant 10 • -30 = -300

Step-2: Find two factors of -300 whose sum equals the coefficient of the middle term, which is 97.

-300 + 1 = -299

-150 + 2 = -148

-100 + 3 = -97

-75 + 4 = -71

-60 + 5 = -55

-50 + 6 = -44

-30 + 10 = -20

-25 + 12 = -13

-20 + 15 = -5

-15 + 20 = 5

-12 + 25 = 13

-10 + 30 = 20

-6 + 50 = 44

-5 + 60 = 55

-4 + 75 = 71

-3 + 100 = 97

Step-3: Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -3 and 100

10x^2 - 3x + 100x - 30

Step-4: Add up the first 2 terms, pulling out like factors:

x • (10x-3)

Add up the last 2 terms, pulling out common factors:

10 • (10x-3)

Step-5: Add up the four terms of step 4:

(x+10) • (10x-3)

Which is the desired factorization

Thus your answer is

$5(x + 10)(10x - 3)$

8 0

2 years ago

Read 2 more answers

The simple interest formula is I = Prt, where I represents simple interest on an amount, P, for t years at a rate of r, where r

andrey2020 [161]

Answer:

$80

Step-by-step explanation:

From the question, we are given The simple interest formula as I = Prt,

where l = simple interest on an amount= $40

t= years=5years

at a rate r= 10%

The rate= 10/100= 0.1

Then since we are looking for P, we can make P subject of formula from this expression;

I = Prt

P=I/rt

P= 40/(0.1 ×5)

P= 40/0.5

P= 80

therefore, the amount of money p that is needed is $80

5 0

3 years ago

Write 41/11 as a decimal

dimaraw [331]

41/11

Simply use your calculator

3.727272....

8 0

2 years ago

Please give me the answer (click on file)

Dovator [93]

Answer:

x = 122

Step-by-step explanation:

5 0

2 years ago

Find the derivative.

krek1111 [17]

Answer:

$\displaystyle f'(x) = \bigg( \frac{1}{2\sqrt{x}} - \sqrt{x} \bigg)e^\big{-x}$

General Formulas and Concepts:

Algebra I

Terms/Coefficients

Expanding/Factoring

Calculus

Differentiation

Derivatives
Derivative Notation

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Derivative Rule [Quotient Rule]: $\displaystyle \frac{d}{dx} [\frac{f(x)}{g(x)} ]=\frac{g(x)f'(x)-g'(x)f(x)}{g^2(x)}$

Step-by-step explanation:

Step 1: Define

Identify

$\displaystyle f(x) = \frac{\sqrt{x}}{e^x}$

Step 2: Differentiate

Derivative Rule [Quotient Rule]: $\displaystyle f'(x) = \frac{(\sqrt{x})'e^x - \sqrt{x}(e^x)'}{(e^x)^2}$
Basic Power Rule: $\displaystyle f'(x) = \frac{\frac{e^x}{2\sqrt{x}} - \sqrt{x}(e^x)'}{(e^x)^2}$
Exponential Differentiation: $\displaystyle f'(x) = \frac{\frac{e^x}{2\sqrt{x}} - \sqrt{x}e^x}{(e^x)^2}$
Simplify: $\displaystyle f'(x) = \frac{\frac{e^x}{2\sqrt{x}} - \sqrt{x}e^x}{e^{2x}}$
Rewrite: $\displaystyle f'(x) = \bigg( \frac{e^x}{2\sqrt{x}} - \sqrt{x}e^x \bigg) e^{-2x}$
Factor: $\displaystyle f'(x) = \bigg( \frac{1}{2\sqrt{x}} - \sqrt{x} \bigg)e^\big{-x}$

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Differentiation

7 0

2 years ago

Describe the graph g < 0.6