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3 years ago

13

One number is 4 times another number and their product is 64. How would that be written in equation form?

2 answers:

Likurg_2 [28]3 years ago

7 0

X x 4 *equal sign* 64 hope this helps. :)

Elina [12.6K]3 years ago

7 0

Or you could write it 6(X)=64

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The following three shapes are based only on squares, semicircles, and quarter circles. Find the perimeter and the area of each

MakcuM [25]

The perimeter = 4 * length of a semicircle of radius 5 == 4* pi * 5 = 20 pi cm

The area of one of the clear parts = 1/2 area of square - area semicircle

= 1/2 * 10^2 - 1/2 pi *5^2 = 50 - 12.5pi

So area of shaded parts = area of square - 4 (50 - 12.5pi)
= 100 - 200 + 100pi = (100pi - 100) cm^2

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4 years ago

28+56t+28w to identify the equivalent expressions.<br> Choose 2 answers:

prohojiy [21]

Answer:

28(1 + 2t + w)

Step-by-step explanation:

This polynomial can be factored by factoring out 28.

28 + 56t + 28w = 28(1 + 2t + w)

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2 years ago

bir su deposu 12 kova su ile doluyor tam dolu olan su deposunun içindeki 5 kovası kullanılıyor depoda kaç kova su kalır

Ksivusya [100]

Answer:

12-5 = 7 olur cevap

Başarılar ☺️

3 0

3 years ago

Usqqe format HTH to mean that the first toss is heads, the second is tails and the third is heads more than one element in the s

Scrat [10]

SOLUTION

Given the question in the image, the following are the solution steps to answer the question.

STEP 1: State the number of outcomes possible for three tossing of a coin

Since a coin has two possible outcomes and is tossed three times, the total outcomes will be:

$\begin{gathered} 2^3=8 \\ 8\text{ outcomes} \end{gathered}$

STEP 2: Find the number of sample spaces for the three tosses

STEP 3: Get the outcomes of the events for which the second toss is tails

Hence, the answers are given as:

Sample Space:

$\lbrace HHH,HHT,HTH,HTT,THH,THT,TTH,TTT\rbrace$

The event that the second toss is tails:

$\lbrace HTH,HTT,TTH,TTT\rbrace$

4 0

1 year ago

4. A random variable X has a mean of 10 and a standard deviation of 3. If 2 is added to each value of X, what will the new mean

Ede4ka [16]

Adding 2 to each value of the random variable $X$ makes a new random variable $X+2$ . Its mean would be

$E[X+2]=E[X]+E[2]=E[X]+2$

since expectation is linear, and the expected value of a constant is that constant. $E[X]$ is the mean of $X$ , so the new mean would be

$E[X+2]=10+2=12$

The variance of a random variable $X$ is

$V[X]=E[X^2]-E[X]^2$

so the variance of $X+2$ would be

$V[X+2]=E[(X+2)^2]-E[X+2]^2$

We already know $E[X+2]=12$ , so simplifying above, we get

$V[X+2]=E[X^2+4X+4]-12^2$

$V[X+2]=E[X^2]+4E[X]+4-12^2$

$V[X+2]=(V[X]+E[X]^2)+4E[X]-140$

Standard deviation is the square root of variance, so $V[X]=3^2=9$ .

$\implies V[X+2]=(9+10^2)+4(10)-140=9$

so the standard deviation remains unchanged at 3.

NB: More generally, the variance of $aX+b$ for $a,b\in\mathbb R$ is

$V[aX+b]=a^2V[X]+b^2V[1]$

but the variance of a constant is 0. In this case, $a=1$ , so we're left with $V[X+2]=V[X]$ , as expected.

5 0

3 years ago