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3 years ago

Calculate the average speed (tin km/hr) of charlie who run to the store 4 km away in 30 minutes

Mathematics

1 answer:

Galina-37 [17]3 years ago

8 0

ANSWER

$8km/hr$

EXPLANATION

The average speed

$= \frac{distance}{time}$

Distance=4km

Time=30mins

Convert time to hours.

Time =0.5hrs

The average speed

$= \frac{4}{0.5}$

$= 8km/hr$

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Evaluate. [(1 1/3−2/3)⋅(−3/4)^3]÷(−2) What is the value of the expression? Enter your answer as a simplified fraction in the box

AleksAgata [21]

Answer

9/64

Step-by-step explanation:

(1 1/3- 2/3) x (-3/4) divided by (-2) is the answer

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7 0

2 years ago

The following table shows the estimated populations and annual growth rates for four countries in the year 2000. Find the

gladu [14]

Answer:

Part 1) Australia $19,751,012\ people$

Part 2) China $1,319,645,764\ people$

Part 3) Mexico $109,712,539\ people$

Part 4) Zaire $60,534,681\ people$

Step-by-step explanation:

we know that

The equation of a exponential growth function is given by

$P(t)=a(1+r)^t$

where

P(t) is the population

t is the number of years since year 2000

a is he initial value

r is the rate of change

Part 1) Australia

we have

$a=19,169,000\\r=0.6\%=0.6\100=0.006$

substitute

$P(t)=19,169,000(1+0.006)^t$

$P(t)=19,169,000(1.006)^t$

Find the expected population in 2025,

Find the value of t

t=2005-2000=5 years

substitute the value of t in the equation

$P(5)=19,169,000(1.006)^5=19,751,012\ people$

Part 2) China

we have

$a=1,261,832,000\\r=0.9\%=0.9\100=0.009$

substitute

$P(t)=1,261,832,000(1+0.009)^t$

$P(t)=1,261,832,000(1.009)^t$

Find the expected population in 2025,

Find the value of t

t=2005-2000=5 years

substitute the value of t in the equation

$P(5)=1,261,832,000(1.009)^5=1,319,645,764\ people$

Part 3) Mexico

we have

$a=100,350,000\\r=1.8\%=1.8\100=0.018$

substitute

$P(t)=100,350,000(1+0.018)^t$

$P(t)=100,350,000(1.018)^t$

Find the expected population in 2025,

Find the value of t

t=2005-2000=5 years

substitute the value of t in the equation

$P(5)=100,350,000(1.018)^5=109,712,539\ people$

Part 4) Zaire

we have

$a=51,965,000\\r=3.1\%=3.1\100=0.031$

substitute

$P(t)=51,965,000(1+0.031)^t$

$P(t)=51,965,000(1.031)^t$

Find the expected population in 2025,

Find the value of t

t=2005-2000=5 years

substitute the value of t in the equation

$P(5)=51,965,000(1.031)^5=60,534,681\ people$

8 0

3 years ago

5 x 100 = ? for easy points

zimovet [89]

Answer:

500! Just multiply 5 x 1 then add the remaining 2 zeros :)

Step-by-step explanation:

Thank you!

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3 years ago

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VashaNatasha [74]

Answer:

Step-by-step explanation:

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2 years ago

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Sidana [21]

Answer:

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Step-by-step explanation:

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2 years ago