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Answer:
we know that, Volume of cube=a³
Let volume of 1st cube be 2x with side a and other be x with side A (according to given ratio)
Step-by-step explanation:
ATQ: 2x=a³ and, x=A³
a=³√2x and, A=x
we know that, surface area of cube is 6a²
Thus, surface area of 1st cube = 6(³√2x)²
= 6³√4x²
Surface area of 2nd cube=6(x)²=6x²
Ratio of S.A=(6³√4x²)÷(6x²)
Ratio of S.A=³√4:1
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Answer:
c-12
Step-by-step explanation:
Pythagoras theorem states that a²+b²=c²
144+b²=c²
b²=c²-144
b=c-12
b=x
x=c-12
2t = 40 - 2w
t = 40/2 (-2/2)w
t = 20 - w -- rearrange
t = -w + 20
t + w = 15
t = -w + 15
same slope, different y intercepts.....parallel lines, no solutions
