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3 years ago

Find an expression equivalent to 1-sinx ^2/1-cosx ^2

Mathematics

1 answer:

madam [21]3 years ago

8 0

Answer:

cot²x

Step-by-step explanation:

Using the identity

sin²x + cos²x = 1, then

1 - sin²x = cos²x

1 - cos²x = sin²x

Thus

$\frac{1-sin^2x}{1-cos^2x}$ = $\frac{cos^2x}{sin^2x}$ = cot²x

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Cherie is jogging around a circular track. She

skelet666 [1.2K]

Answer:

Measure of minor angle JOG is $95.5^{\circ}$

Step-by-step explanation:

Consider a circular track of radius 120 yards. Assume that Cherie starts from point J and runs 200 yards up to point G.

$\therefore m JG = 200 yards, JO=120 yards$ .

Now the measure of minor arc is same as measure of central angle. Therefore minor angle is the central angle $\angle JOG = \theta$ .

To calculate the central angle, use the arc length formula as follows.

$Arc\:Length\left(s\right) = r\:\theta$

Where $\theta$ is measured in radian.

Substituting the value,

$200=120\:\theta$

Dividing both side by 120,

$\dfrac{200}{120}=\theta$

Reducing the fraction into lowest form by dividing numerator and denominator by 40.

$\therefore \dfrac{5}{3}=\theta$

Therefore value of central angle is $\angle JOG = \theta=\left(\dfrac{5}{3}\right)^{c}$ , since angle is in radian

Now convert radian into degree by using following formula,

$1^{c}=\left(\dfrac{180}{\pi}\right)^{\circ}$

So multiplying $\theta$ with $\left(\dfrac{180}{\pi}\right)^{\circ}$ to convert it into degree.

$\left(\dfrac{5}{3}\right)^{c}=\left(\dfrac{5}{3}\right) \times \left(\dfrac{180}{\pi}\right)^{\circ}$

Simplifying,

$\therefore \theta = 95.49^{circ}$

So to nearest tenth, $\angle JOG=95.5^{circ}$

8 0

3 years ago

What is the area underneath a normal curve always equal to?

Pani-rosa [81]

The correct answer is C. One

3 0

2 years ago

Read 2 more answers

Enter the range of values for x: B 15 2x - 10 С 48° A 18 [?] Enter

SOVA2 [1]

<h3>Answer: 5 < x < 29</h3>

=========================================

Explanation:

Since AB is smaller than AD, this must mean the angle ACB is smaller than angle ACD. Note how these angles are opposite the sides mentioned.

So 2x-10 < 48

At the same time, 2x-10 is also larger than 0.

Overall, we can say 0 < 2x-10 < 48

---------

Let's solve for x

0 < 2x-10 < 48

0+10 < 2x < 48+10 ...... add 10 to all sides

10 < 2x < 58

10/2 < x < 58/2 ..... divide all sides by 2

5 < x < 29

8 0

3 years ago

Line GJ is tangent to point A at point G. If AI = 5 and IF = 12, find A F.

Drupady [299]

I believe this is how you do it...
AI=5, 5 squared=25
IF=12, 12 squared=144
144+25 (only because line A F is bigger than AI or IF does it add)
A F=169

6 0

2 years ago

Read 2 more answers

In a circle with a diameter of 25.2 ft, an arc is intercepted by a central angle of 168º.

Rina8888 [55]

Answer:

$36.93\ ft$

Step-by-step explanation:

step 1

Find the circumference of the circle

The circumference is equal to

$C=\pi D$

we have

$D=25.2\ ft$

substitute

$C=25.2\pi\ ft$

step 2

we know that

The circumference of a circle subtends a central angle of 360 degrees

using proportion

Find out the arc length by a central angle of 168 degrees

$\frac{25.2\pi}{360}=\frac{x}{168}\\\\x=25.2\pi*168/360\\\\x=(25.2*3.14)*168/360\\\\x=36.93\ ft$

3 0

2 years ago