Find an expression equivalent to 1-sinx ^2/1-cosx ^2

Mathematics

1 answer:

madam [21]3 years ago

8 0

Answer:

cot²x

Step-by-step explanation:

Using the identity

sin²x + cos²x = 1, then

1 - sin²x = cos²x

1 - cos²x = sin²x

Thus

$\frac{1-sin^2x}{1-cos^2x}$ = $\frac{cos^2x}{sin^2x}$ = cot²x

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Answer:

53 52 72 61 68 58 47 47 (arrange it)

47 47 52 53 58 61 68 71 (done!)

Mode: 47 (appear twice)

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Answer:

The answer is B.) The diameter of the fir tree when planted and 20 inches

Step-by-step explanation:

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Answer:

0.0782 (7.82%)

Step-by-step explanation:

The required probability will be found by using the Binomial Distribution which fits the case of n independent events each with a probability of success equal to p with k successes.

The PMF (Probability Mass Function) is

$f(k,n,p)=\binom{n}{k}p^kq^{n-k}$

Where $q = 1-p$

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$f(1,50,0.0017)=\binom{50}{1}0.0017^10.9983^{49}=0,0782$