The answer is b.6, you set up a proportion of the corresponding sides in both triangles...12/9=8/x solve for x and get 6.
Hello,
A: roots: -1,-3
a point (-2,1)
Vertex=((-2,1)
y=k*(x+1)(x+3) using roots
but k*(-2+1)(-2+3)=1==>k*(-1)*1=1==>k=-1
eq: y=-(x+1)(x+3)
==>y=-(x²+3x+x+3)
==>y=-x²-4x-3
y=k(x+2)²+1 if x=-1,y=0 ==>k*1+1=0==>k=-1
==>y=-(x+2)²+1
Answer :A--> R,K
B)
y=k(x+4)²-2 and k=-1/2
y=-1/2(x+4)²-2
y=-1/2x²-4x-10
answer B--> I,≈W if it is written -1/2*x² (square has been forgotten)
C:
y=2x²-16x+30
y=2(x-4)²-2
answer : C-->S,J
D:
y=-(x+3)(x+1)
y=-x²-4x-3
=-(x+2)²+1
answer D--> V,L
E:
Here there is a problem: or the graph is wrong, or 2 equations are missing!
y=1(x+1)(x-3) using roots
y=x²-2x-3 ≈ T si it were -2x and not +2x.
y=(x-1)²-4 ≈H is it were -1 in place of +1 [H:y=(x+1)²-4]
First it is reflected in the x axis (beacuse the x value becomes negative but the y values stays the same)
second its dilated by a factor of a half ( the sides of the figure are reduced by a half)
then its translated 2 units to the left and 2 units upwards
Answer:
2/3a^5
Step-by-step explanation:
we know that 2/7x2/7x2/7 = 8/27
a^15 cube will be a^5
because we know (2^3)^2 = 2^6
so (a^5)^3 = a^15
2/3a^5
|x + 2| + 16 = 1
<u> - 16 - 16</u>
|x + 2| = -15
x + 2 = -15 U x + 2 = 15
<u> - 2 - 2</u> <u> - 2 - 2</u>
x = -17 x = 13
|2x + 6| - 4 = 20
<u> + 4 + 4</u>
|2x + 6| = 24
2x + 6 = 24 U 2x + 6 = -24
<u> - 6 - 6</u> <u> - 6 - 6</u>
<u>2x</u> = <u>18</u> <u>2x</u> = <u>-30</u>
2 2 2 2
x = 9 x = -15
