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satela [25.4K]
3 years ago
14

Can u get me the answer to number 1 of all the letters

Mathematics
1 answer:
Afina-wow [57]3 years ago
7 0

Answer:

A=103 B=103 C=83 D=83 E=168

Step-by-step explanation:


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Chapter 9 TRP 9-1 Assume the taxpayer does NOT wish to contribute to the Presidential Election Fund, unless otherwise stated in
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Answer:

Chapter 9 TRP 9-1

Assume the taxpayer does NOT wish to contribute to the Presidential Election Fund, unless otherwise stated in the problem.

 

Assume all taxpayers did NOT receive, sell, send, exchange, or otherwise acquire any financial interest in any virtual currency during the year.

 

Juliette White is a head of household taxpayer with a daughter named Sabrina. They live at 1009 Olinda Terrace, Apartment 5B, Reno, NV 78887. Juliette works at a local law firm, Law Offices of Dane Gray, and attends school in the evenings at Reno Community College (RCC). She is taking some general classes and is not sure what degree she wants to pursue yet. She is taking three units this semester. Full-time status at RCC is nine units. Juliette’s mother watches Sabrina after school and in the evenings (no charge) so that Juliette can work and take classes at RCC. Social security numbers are 412-34-5670 for Juliette and 412-34-5672 for Sabrina. Their birth dates are as follows: Juliette, 10/31/1988; and Sabrina, 3/1/2013.

The Form W-2 Juliette received from the Law Offices of Dane Gray contained the following information:

 

Wages (box 1) = $ 29,502.30

Federal W/H (box 2) = $ 1,007.14

Social security wages (box 3) = $ 29,502.30

Social security W/H (box 4) = $ 1,829.14

Medicare wages (box 5) = $ 29,502.30

Medicare W/H (box 6) = $ 427.78

 

Juliette also had the following expenses:

Education expenses:  

Tuition for Reno Community College $ 775

 

Prepare Juliette’s federal tax return. Use Form 1040 and any additional appropriate schedules or forms she may need for credits. For any missing information, make reasonable assumptions. (Input all the values as positive numbers. Instructions can be found on certain cells within the forms. Round your final answers to the nearest whole dollar amount. Do not skip rows, while entering in Dependents section of Form 1040 PG1.)

 

Use the appropriate Tax Tables and EIC table.

 

rev: 03_17_2021_QC_CS-257838

Step-by-step explanation:

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a) The stem and leaf plot for the data can be comfortably obtained from the excel option as follows: XL STAT option in excel as follows:
1. In excel sheet choose XL STAT
2. Then in that choose the visualizing data- uni-variate plots.
3. In univariate plot – chart -select the stem and leaf plot.
4. In quantitative data select the data set and click ok.
A summary of the statistics and a stem and leaf plot can be obtained as follows.
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3 years ago
Each month, 8 magazines arrive at Sydney's home. Write an equation that would show the number of motnths (n) it took for Sydney
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3 years ago
16 is what percent of 34? Round your answer to the nearest tenth of a percent if necessary.
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4 0
3 years ago
Read 2 more answers
¿Para cuál(es) valor(es) de p las rectas de ecuación x − 1/p = 2 − y/p y x − 1/1 − p = y − 2/2 son perpendiculares? A) Solo para
Akimi4 [234]

Respuesta:

C) Solo para el -1

Explicación paso a paso:

Para resolver este problema, debemos de determinar la pendiente en cada una de las ecuaciones provistas:

\frac{x-2}{p}=\frac{2-y}{p}

y

\frac{x-1}{1-p}=\frac{y-2}{2}

ahora bien, necesitamos conocer el valor de la pendiente de una de las dos ecuaciones. Tomemos la primera ecuación y resolvámosla para y:

\frac{x-2}{p}=\frac{2-y}{p}

Multiplicamos ambos lados para p y obtenemos:

x-1=2-y

volteamos la ecuación y nos da:

2-y=x-1

pasamos el 2 a restar al otro lado y nos da:

-y=x-1-2

-y=x-3

y dividimos ambos lados de la ecuación dentro de -1

y=-x+3

esta ecuación ya tiene la forma pendiente intercepto:

y=mx+b

donde m es nuestra pendiente:

m_{1}=-1

Esta es la pendiente de una de las dos ecuaciones, para que la segunda ecuación sea perpendicular a la primera, su pendiente debe de ser el recíproco negativo de la pendiente de la primera ecuación, entonces la pendiente de la segunda ecuación debe ser:

m_{2}=-\frac{1}{m_{1}}

m_{2}=-\frac{1}{-1}

m_{2}=1

ahora tomamos la segunda ecuación y encontramos su pendiente. Tomemos la ecuación:

\frac{x-1}{1-p}=\frac{y-2}{2}

y despejemos y, comenzamos multiplicando ambos lados de la ecuación por 2, así que obtenemos:

2\frac{x-1}{1-p}=y-2

Multiplicamos el 2 por cada término de la fracción, entonces obtenemos:

\frac{2x-2}{1-p}=y-2

ahora pasamos el 2 a sumar al lado izquierdo y obtenemos:

\frac{2x-2}{1-p}+2=y

Ahora podemos separar la fracción del lado izquierdo en dos fracciones para obtener:

\frac{2x}{1-p}-\frac{2}{1-p}+2=y

volteamos la ecuación y nos da:

y=\frac{2x}{1-p}-\frac{2}{1-p}+2

Ahora nuestra ecuación ya tiene la forma y=mx+b

de aquí podemos determinar nuestra pendiente:

m=\frac{2}{1-p}

Con la primera ecuación determinamos que esta pendiente debería de ser igual a 1, entonces igualamos esa segunda pendiente a 1 para obtener:

\frac{2}{1-p}=1

y despejamos p

Pasamos a multiplicat el 1-p al lado derecho de la ecuación para obtener:

2=1-p

volteamos la ecuación:

1-p=2

pasamos el 1 a restar al lado derecho:

-p=2-1

-p=1

y multiplicamos ambos lados de la ecuación por -1 para obtener:

p=-1

Entonces la respuesta es C) solo para el -1

4 0
3 years ago
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