For any function y = mx+b , m is rate of change and , b is the y intercept
]Function 1 is
y = 20x + 15,
where rate of change = 20 and y intercept = 15
And for function 2 , we can write the function as y= 10x +25
rate of change = 10 and y intercept = 25
So the statements which are true are
Function 1 has a greater rate of change than function 2.
Function 2 has a greater y-intercept than function 1.
Answer:
C.There is no difference they are calculated the same.
Step-by-step explanation:
If it's wrong so please sorry
Answer:
±11.18
Step-by-step explanation:
the function is:
and to find the roots we need to find which values of 
makes the function result in zero:
solving for :
A square root has two solutions, one positive and one negative, so the solutions are:
±
≈ ±11.18
the roots of the quadratic equation are +11.18 and -11.18
By replacing you get:
5*7-2*11+3*(-1) = 35-22-3= 10
so the answer is 10.
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Answer:
number of terms=9
Step-by-step explanation:
![t_{1}=6\\t_{5}=18\\\\t_{n}=t_{1}+(n-1)d\\18=6+(5-1)d\\18-6=4d\\4d=12\\d=12/4=3\\s_{n}=162\\s_{n}=\frac{n}{2}[2t_{1}+(n-1)d]\\162=\frac{n}{2}[2(6)+(n-1)3]\\162 \times 2=n(12+3n-3)\\324=n(3n+9)\\3n^2+9n-324=0\\n^2+3n-108=0\\n^2+12n-9n-108=0\\n(n+12)-9(n+12)=0\\(n+12)(n-9)=0\\n=-12,9\\n=-12 (rejected)](https://tex.z-dn.net/?f=t_%7B1%7D%3D6%5C%5Ct_%7B5%7D%3D18%5C%5C%5C%5Ct_%7Bn%7D%3Dt_%7B1%7D%2B%28n-1%29d%5C%5C18%3D6%2B%285-1%29d%5C%5C18-6%3D4d%5C%5C4d%3D12%5C%5Cd%3D12%2F4%3D3%5C%5Cs_%7Bn%7D%3D162%5C%5Cs_%7Bn%7D%3D%5Cfrac%7Bn%7D%7B2%7D%5B2t_%7B1%7D%2B%28n-1%29d%5D%5C%5C162%3D%5Cfrac%7Bn%7D%7B2%7D%5B2%286%29%2B%28n-1%293%5D%5C%5C162%20%5Ctimes%202%3Dn%2812%2B3n-3%29%5C%5C324%3Dn%283n%2B9%29%5C%5C3n%5E2%2B9n-324%3D0%5C%5Cn%5E2%2B3n-108%3D0%5C%5Cn%5E2%2B12n-9n-108%3D0%5C%5Cn%28n%2B12%29-9%28n%2B12%29%3D0%5C%5C%28n%2B12%29%28n-9%29%3D0%5C%5Cn%3D-12%2C9%5C%5Cn%3D-12%20%28rejected%29)
as number of terms can't be negative.
