I'm not sure where a is supposed to be in this equation, but I'm going to assume it's supposed to be written as either 3a x 4b = 54, or 304b = 54a. If it's something else, let me know, but I'll just answer these two for now.

1. 3a x 4b

So we know that b is equal to 9. Therefore, we can rewrite

$3a \times 4b = 54$

$3a \times 4(9) = 54$

To get rid of a multiplier on one side, divide both sides by the number you want gone. I'll use 4(9), which equals 36.

$3a = 54 \div 36 = 1.5$

Then we can divide by 3 to get

$a = 1.5 \div 3 = 0.5$

0.5 isn't a viable answer, so I'll try the second interpretation.

2. 304b = 54a

This one is a bit easier. All we need to do is divide both sides by 54 to get

$304b \div 54 = a$

304 x 9 = 2736

2736/54 = 50.66...

Again, not a viable answer. Please edit your question to include a and I'll give it another shot!

5 0

1 year ago

Yall please help meee

Lady_Fox [76]

Answer:

<u>12n + 2</u>

Step-by-step explanation:

$w(n) = un + 2$

$w(3n) = 4(3n) + 2$

$ans = 12n + 2$

hope it helps you

have a great day!!

6 0

2 years ago

Is 21 a multiple of 6

JulijaS [17]

No, 21 is a multiple of 7

8 0

2 years ago

I could use help with these please with the work and an explanation​

I could use help with these please with the work and an explanation