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HACTEHA [7]
3 years ago
14

Using the net below, find the surface area of the pyramid. (in the image) 2in 3in 3in​

Mathematics
1 answer:
hoa [83]3 years ago
4 0

Answer:

Surface area = 21 in.²

Step-by-step explanation:

Surface area of the pyramid = sum of all areas of the faces or parts of the net = 4(area of triangle) + area of square base

✔️Area of the four triangles:

A = 4(½*b*h)

Where,

b = 3 in.

h = 2 in.

A = 4(½*3*2)

A = 2*3*2

A = 12 in.²

✔️Area of the square base = s²

s = 3 in.

Area = 3² = 9 in.²

✅Surface area of the pyramid = 12 + 9 = 21 in.²

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Your y intercept is 1.

Step-by-step explanation:

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and if you solve that, 2x1=2, 3-2=1.

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3 years ago
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The arrow of this spinner was spun 60 times. On 45 out of 60 times, the arrow landed on a section with a multiple of 4. What was
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PLEASE HELP WITH THIS QUESTION!! DUE BY 1PM! wILL RATE YOU GOOD!! THANK YOU!!
kupik [55]
Find a_{1} by plugging in 1 into n:
a_{1} = 98-2(1)=96

Find a_{11 by plugging in 11 into n:
a_{11} = 98-2(11)
a_{1} =98-22=76

Now to find the sum your formula is:
S_{n} = \frac{n}{2} ( a_{1} + a_{n})
n = 11,   a_{1} = 96 ,  a_{11} =76

Now plug that into the formula
S_{11} = \frac{11}{2} (96+76)
S_{11} = 5.5(172)=946

Hope that helps
8 0
3 years ago
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