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lara [203]
2 years ago
5

Joe runs each lap in 5 minutes. He will run at least 12 laps today. What are the possible numbers of minutes he will run today?

Use for the number of minutes he will run today. Write your answer as an inequality solved for .
Mathematics
2 answers:
worty [1.4K]2 years ago
8 0

Answer:

at least 60 min (1 hour)

Step-by-step explanation:

we know that a lap takes 5 min.

and we know he will run At least 12 laps

that means that the least number of min.he can run is 5x12=60

So, 60min is the answer

Marina CMI [18]2 years ago
5 0

Answer:

5m ≥ 12; 1 hour

Step-by-step explanation:

you can represent the number of minutes per mile by 5m, but he is running 12 laps. So therefore, he would run for 60 minutes, or 1 hour. 5m ≥ 12

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What is the value of y?
NNADVOKAT [17]

Answer:

y = 40

Step-by-step explanation:

Lets make an equation to represent the sum of the angles:

We know that the sum of angles of triangles equals 180 degrees. So based on this knowledge, the equation is :

2y + y + 10 + 50 = 180


Now we simplify:

2y + y = 3y


10 + 50 = 60


So our new equation is 3y + 60 = 180

Now all we have to do is simplify:

3y + 60 = 180

3y + 60 -60 = 180 - 60

3y = 120

3y / 3 = 120 / 3

y = 40


So the answer is 40 hope this helped


7 0
2 years ago
Brian can type 1 and one-third pages every 20 minutes. How many pages can he type in 2.5 hours? 7.5 pages 10 pages 22.5 pages 20
vladimir2022 [97]

Answer:

10 pages

Step-by-step explanation:

1 and 1/3 pages multiplies by 7.5 brings us to the answer of ten pages

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5 0
3 years ago
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A pet store donated a percent of every sale to hospitals. The total sales were $8,750 so the store
Salsk061 [2.6K]

Divide the amount donated by total sales then multiply by 100.

350 / 8750 = 0.04

0.04 x 100 = 4%

5 0
3 years ago
Help with this question please help
levacccp [35]
Slope is 2
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8 0
2 years ago
Rectangle ABCD is graphed in the coordinate plane. The following are the vertices of the rectangle: A(3,−2), B(6, -2), C(6, 5) D
Vikki [24]

Answer:

Step-by-step explanation:

Distance=\sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}} \\

A(3,-2) ;  B(6,-2)

AB=\sqrt{(6-3)^{2}+(-2-[-2])^{2}}\\\\ =\sqrt{3^{2}+(-2+2)^{2}}\\\\=\sqrt{9+0}=\sqrt{9}\\\\

AB = 3 units

B(6,-2) ;  C(6,5)

BC=\sqrt{(6-6)^{2}+(5-[-2])^{2}} \\\\=\sqrt{0+(5+2)^{2}}\\\\=\sqrt{(7)^{2}}\\

BC = 7 units

Area of rectangle = length * width

                             = AB * BC

                             = 3 * 7

                             = 21 square units

3 0
3 years ago
Read 2 more answers
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