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Nostrana [21]
3 years ago
5

What is the solution to 4+5eX+2 = 11?

Mathematics
1 answer:
Tom [10]3 years ago
3 0

Answer:

B

Step-by-step explanation:

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Angles a and e! they’re alternate interior angles, therefore they are congruent.
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3 years ago
The zeros of a parabola are 6 and −5. If (-1, 3) is a point on the graph, which equation can be solved to find the value of a in
Elena L [17]

ANSWER

3= a( - 1 +6)( - 1  - 5)

EXPLANATION

The equation of a parabola in factored form is

y = a(x + m)(x + n)

where 'a' is the leading coefficient and 'm' and 'n' are the zeros.

From the question, the zeros of the parabola are 6 and −5.

This implies that,

m = 6 \:  \: and \:  \: n =  - 5

We plug in these zeros to get:

y= a(x +6)(x  - 5)

If (-1, 3) is a point on the graph of this parabola,then it must satisfy its equation.

We substitute x=-1 and y=3 to obtain:

3= a( - 1 +6)( - 1  - 5)

The first choice is correct.

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4 years ago
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(6x^3 + 4x^2 + 2x) ÷ 2x<br>Answer fast plz..​
Phoenix [80]

refer to the attachment okay

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What are the x- and y-intercepts of the function graphed below?*
My name is Ann [436]

Answer:

(3,0) and (0,6)

Step-by-step explanation:

(x,y) is the only way to make ordered pair.

The x was a 3 so you could cross out the first and last because they put the 3 in the y spot. When is should be (3,0).

Then the y was 6 and that I would be (0,6) so the third would also be crossed out because they put the 6 in the y spot.

So the answer is (3,0) and (0,6).

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3 years ago
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In an experiment to measure the lifetimes of parts manufactured from a certain aluminum alloy, 73 parts were loaded cyclically u
kari74 [83]

Answer:

0.0094.

Step-by-step explanation:

For the given experiment, let X be the lifetimes of parts manufactured from a certain aluminum alloy.

sample size =73

Sample mean = 784

Sample standard deviation = 120

Let µ represent the mean number of kilocycles to failure for parts of this type.

Null hypothesis, H0 : µ ≤ 750

Alternative hypothesis, H1 : µ > 750.

z=\dfrac{\overline{X}-\mu}{\frac{s}{\sqrt{n}}}

where,

\overline{X} is sample mean.

\mu is population mean.

s is sample standard deviation.

n is the sample size.

z=\dfrac{783-750}{\frac{120}{\sqrt{73}}}

z=2.35

It is a right tailed test because alternative hypothesis is µ > 750. So, P-value is the probability of observing a sample mean greater that 783 or the probability of P(z>2.35).

P=P(z>2.35)

P=1-P(z

P=1-0.9906

P=0.0094

Therefore the P-value is 0.0094.

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