Answer:
10=y/11-13
We move all terms to the left:
-10-(y/11-13)=0
-y/11+13-10=0
We multiply all the terms by the denominator
-y+13*11-10*11=0
We add all the numbers together, and all the variables
-1y+33=0
We move all terms containing y to the left, all other terms to the right
-y=-33
y=-33/-1
y=+33
First, put it into slope/intercept form so you can see what you've got.
"Slope/intercept form" is <em> y = everything else</em> .
So that means you have to take the equation you have and "solve it for 'y' ".
<u>2y - 10x = 20</u>
Add 10x to each side: 2y = 10x + 20
Divide each side by 2 : <em> y = 5x + 10</em>
There it is.
Now that you have it in that form, you can just look at it and see that the
slope of the line on the graph is 5, and the line crosses the y-axis at 10.
And that's exactly the information you need to graph it. On your graph,
mark a little dot on the y-axis at 10, and draw a line through that dot
with a slope of 5.
Answer:
243 cm^2 + 108 cm^2 = 351 cm^2
Step-by-step explanation:
So, we have a rectangle and two triangles, we know all the sides or angles.
Rectangle: with 9 cm lenght 15cm + 12 cm = 27 cm
Formula: A=wl -> A=9*27 = 243 cm^2
Trianlge: A=ab/2
Angle 90°
Side A 12 cm
Side B 18 cm - 9 cm = 9 cm
A=ab/2=12·9/2=54 cm times 2 (for the opposite side) = 108 cm^2 = 351 cm^2
Step-by-step explanation:
1) The area of rectangle is ( 30x²y + 20xy ) cm² and its breadth is 10xy cm .Find its length....
= Solution ,
Length ( L ) = ?
breadth ( b ) = 10xy cm
area ( a ) = ( 30x² + 20xy )
Now ,
area ( a ) = l × b
or, ( 30x²y + 20xy ) = L × 10xy cm
2) Subtract the quotient when 20x⁴y² is divided by 5x³y from the product of 2x and 3y.
= Solution,
The product of 3x and 4y = 6xy
= 6x - 4xy
hope it helped !!!!
Answer:
If we assume a temperature of 20ºc and the blood interfacial surface tension is similar to water interfacial surface tension, the diameter of the capillary tube should be 0.933mm.
Step-by-step explanation:
The Jurin law describes the height a fluid can reach in a capillary tube. This law can be written as:
where γ is the interfacial surface tension, θ is the contact angle with the fluid, ρ is the fluid density, g is the gravity acceleration and r is the tube radius.
If we assume that the interfacial surface tension of blood and water are almost the same, γ=0,0728 N/m at 20ºc. Therefore the diameter of the tube will be:
