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3 years ago

Is the relation a function? {(10,5), (1, 8), (3, 3), (4, 2), (1, 7)}

Mathematics

2 answers:

AnnyKZ [126]3 years ago

7 0

yes because none of the x values are the same bb ♡

astraxan [27]3 years ago

7 0

Answer:

Yes.

Step-by-step explanation:

A function is when none of the inputs are the same. In this case, the inputs are the x values. Since no x values are repeated, this relation is a function.

~Luna P.

^_^

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the area of a gymnasium floor is 264 square yard. the floor is 11 yards wide . how long is the floor?

Alekssandra [29.7K]

Area = Length x Width (A = L x W)

A = 264, W = 11, L = ?

Rewrite the equation to find L. In order to reverse multiplication, you must divide.

L = A / W

L = 264 / 11 = 24 yards

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3 years ago

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Two lines, A and B, are represented by equations given below: Line A: y = x − 4 Line B: y = 3x + 4 Which of the following shows

Ede4ka [16]

(-4,-8) because it satisfies both equations

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Evaluate the integral. (Assume a ≠ b. Remember to use absolute values where appropriate. Use C for the constant of integration.)

Bess [88]

Answer:

F(x)= 5*[ $\frac{x^{3} }{3}$ + (a*b)* $\frac{x^{2} }{2}$ + a*b*x + C.

Step-by-step explanation:

First step we aplicate distributive property to the function.

5*(x+a)*(x+b)= 5*[ $x^{2}$ +x*b+a*x+a*b]

5*[ $x^{2}$ +x*(b+a)+a*b]= f(x), where a, b are constant and a≠b

integrating we find ⇒∫f(x)*dx= F(x) + C, where C= integration´s constant

∫^5*[ $x^{2}$ +x*(a+b)+a*b]*dx, apply integral´s property

5*[∫ $x^{2}$ dx+∫(a*b)*x*dx + ∫a*b*dx], resolving the integrals

5*[ $\frac{x^{3} }{3}$ + (a*b)* $\frac{x^{2} }{2}$ + a*b*x

Finally we can write the function F(x)

F(x)= 5*[ $\frac{x^{3} }{3}$ + (a*b)* $\frac{x^{2} }{2}$ + a*b*x ]+ C.

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3 years ago

For integers a, b and k, we know that a >12, b > 20 and a < b. If b=7k, what is the value of k ?

Doss [256]

This question is incomplete, the complete question is;

For integers a, b and k, we know that a > 12, b < 20 and a < b. If b=7k, what is the value of k ?

Answer: the value of k = 2

Step-by-step explanation:

Given that;

a > 12

b < 20

a < b

If b = 7k

Now if k = 1 {b = 7k = 7}

b would be equal to 7 but b has to be greater than 20

IT CANT BE

if k = 2 { b = 7k = 14}

b would be equal to 14, a is greater than 12, b has to be less than b; 14 < 20,

a has to be less than than b ( 12 < 14 )

IT IS

if k = 3 {b = 7k = 21}

b would be equal to 21, so b is greater than 20 and a is less than 21

IT CANT BE

Therefore the value of k = 2

5 0

3 years ago

A particle moves along a line so that its position at any time t > 0 is given by the function s(t) = - t3 + 7t2 - 14t +8 wher

eimsori [14]

Answer:

s(5) = -12

Step-by-step explanation:

s(t) = - t³ + 7t² - 14t +8

Find the displacement during the first 5 seconds.

When t = 5

s(t) = - t³ + 7t² - 14t +8

s(5) = -5³ + 7(5)² - 14(5) + 8

= -125 + 7(25) - 70 + 8

= -125 + 175 - 70 + 8

= -12

s(5) = -12

4 0

3 years ago