Assume (a,b) has a minimum element m.
m is in the interval so a < m < b.
a < m
Adding a to both sides,
2a < a + m
Adding m to both sides of the first inequality,
a + m < 2m
So
2a < a+m < 2m
a < (a+m)/2 < m < b
Since the average (a+m)/2 is in the range (a,b) and less than m, that contradicts our assumption that m is the minimum. So we conclude there is no minimum since given any purported minimum we can always compute something smaller in the range.
Answer:
y≥1/2 x +1
Step-by-step explanation:
first the line in the graph is bold and not dotted
so the sign is either ≤ or≥
the shaded area is on the top , on this case it is greater than
the right answer is y≥1/2 x +1
The momentum formula is
p = m*v
where,
p = momentum (not sure why p is chosen but many physics books tend to pick this letter)
m = mass in kilograms
v = velocity in meters per second
So let's calculate the momentum for the 4500 kg vehicle
p = m*v
p = 4500*85
p = 382500 kg m/s
And let's do the same for the 3700 kg vehicle
p = m*v
p = 3700*85
p = 314500 kg m/s
Answer:-21
Step-by-step explanation:
23+22=45
45-24=21
then flip 24 and 45 to get negative
Answer:
7f lenghtg is 29.2
Step-by-step explanation:
