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3 years ago

15

You paid $700 for a new guitar. Your guitar cost $20 less than twice the cost of your friend's guitar.

2 answers:

lapo4ka [179]3 years ago

4 0

Answer: i get $340

Step-by-step explanation:

700-20= 680

680÷2= 340

Another way to look at it is :

Let p =friends guitar

2p= twice

2p+20=700

2p=700-20

2p=680

P= 680÷2

P=340 is friends guitar

dedylja [7]3 years ago

4 0

Your friends guitar would have costed $1380

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Can someone help me with real numbers

Ierofanga [76]

Answer:

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Explanation:

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7 0

3 years ago

There are a total of 64 students in a drama club and a yearbook club. The drama club has 10 more students than the yearbook club

g100num [7]

Given:
64 total students
x = drama club students
y = yearbook club students

x = y + 10
y = 64 - x

y = 64 - x
y = 64 - (y + 10)
y = 64 - y - 10
y + y = 64 - 10
2y = 54
2y/2 = 54/2
y = 27

x = y + 10
x = 27 + 10
x = 37

To check:

x + y = 64
37 + 27 = 64
64 = 64

8 0

4 years ago

One container is filled with mixture that is 25% acid. A second container is filled with a mixture that is 55% acid. The second

algol13

Answer:

Therefore the third container contains $\frac{735}{17}\%$ = 43.23 % acid.

Step-by-step explanation:

Given that, One container is filled with the mixture that 25% acid. 55% acid is contain by second container.

Let the volume of first container be x cubic unit.

Since the volume of second container is 55% larger than the first.

Then the volume of the second container is

$= (V\times \frac{100+55}{100})$ cubic unit.

$=\frac{155}{100}V$ cubic unit.

The amount of acid in first container is

$=V\times \frac{25}{100}$ cubic unit.

$=\frac{25}{100}V$ cubic unit.

The amount of acid in second container is

$=(\frac{155}{100}V \times \frac{55}{100})$ cubic unit.

$=\frac{8525}{10000}V$ cubic unit.

Total amount of acid $=(\frac{25}{100}V+\frac{8525}{10000}V)$ cubic unit.

$=(\frac{2500+8525}{10000}V)$ cubic unit.

$=(\frac{11025}{10000}V)$ cubic unit.

Total volume of mixture $=(V+\frac{155}{100}V)$ cubic unit.

$=\frac{100+155}{100}V$ cubic unit.

$=\frac{255}{100}V$ cubic unit.

The amount of acid in the mixture is

$=\frac{\textrm{The volume of acid}}{\textrm{The amount of mixture}}\times 100 \%$

$=\frac {\frac{11025}{10000}V}{\frac{255}{100}V}\times 100\%$

$=\frac{735}{17}\%$

Therefore the third container contains $\frac{735}{17}\%$ acid.

5 0

3 years ago

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nlexa [21]

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Answer:

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