The angles and side lengths for both triangles are;
3) A = 36°; B = 54°; C = 90°; a = 7; b = 9.63; c = 4.11
4) A = 64°; B = 26°; C = 90°; a = 1.798; b = 0.88; c = 2
<h3>How to solve Pythagoras theorem?</h3>
3) From the diagram, we are already given;
B = 54°
C = 90°
a = 7
We know that sum of angles in a triangle is 180° and so;
A = 180 - (90 + 54)
A = 36°
By trigonometric ratios;
b/7 = tan 54
b = 7 * tan 54
b = 7 * 1.376
b = 9.63
7/c = cos 54
c = 7 * cos 54
c = 4.11
4) From the diagram, we are already given;
B = 26°
C = 90°
c = 2
We know that sum of angles in a triangle is 180° and so;
A = 180 - (90 + 26)
A = 64°
By trigonometric ratios;
b/2 = sin 26
b = 2 * sin 26
b = 2 * 0.4384
b = 0.88
a/2 = cos 26
a = 2 * cos 26
a = 1.798
Read more about Pythagoras Theorem at; brainly.com/question/654982
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Rick is 27 years old. Pretend D is David and R is Rick
D+R=81
D=2R
2R+R=81 ---> 3R=81 ---> 81/3=R R=27 3(27)=81 TRY IT!
Answer:
Range of the function → {24, 375}
Step-by-step explanation:
Domain of the function f(x) = 3x³ is {2, 5}
we have to find the range when its domain is {2, 5}
Since x-values of any function define the domain and y-values define the range.
For x = 2,
f(2) = 3(2)³ = 24
For x = 5,
f(5) = 3(5)³ = 375
Therefore, range of the given function for the given domain will be {24, 375}.
I believe the answer would be D.
