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Irina18 [472]
3 years ago
8

Subtract. use a grid to record the problem. 637350-43832

Mathematics
1 answer:
garik1379 [7]3 years ago
3 0
593518 I do believe that is right
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rachel breaks up a large array into two smaller arrays. the two smaller arrays show 3 times five and 4 times 5. what was the lar
SVEN [57.7K]

Answer:

So the bigger array is 12 and 25

Step-by-step explanation:

Let's do a multiplication of this array first and Know it's result.

3 times five and 4 times 5. = (3*5) and (4*5)

= 15 and 20

Multiplying further gives us

= 15 * 20=300.

So to combine to get the bigger array.

We must get back 300 as the result of our product.

Let's multiply the row(x) with the row(x)

And the column (y) with column(y)

3 times five and 4 times 5.= 3*4 and 5*5

So the bigger array is 12 and 25

To check.

12*25 = 300

Proved.

4 0
4 years ago
The sum of two consecutive odd integers is 28. What are the integers?
Fantom [35]
The correct option is B): "<span>Let x = 1st integer. Let x + 2 = 2nd integer.</span><span>"
Given that "The sum of two consecutive odd integers is 28."
 
Now the difference between two odd numbers is 2. So this means that one odd number has to be greater than the other by 2.

Let the smaller number be 'X' therefore the bigger number will be 'x+2' thus x + (x+2) = 28
 
therefore, x + x + 2 = 28 now we subtract "2" from both the sides
therefore, 2x = 26 now dividing throughout by 2 we get:

x = 13 therefore, x + 2 = 13+2
                                    = 15
 
therefore, the numbers are 13 AND 15</span>
4 0
4 years ago
The chart lists four different kinds of atoms.
iogann1982 [59]

The answer is they cannot be divided

6 0
3 years ago
If g(x)=8x^6 and f(x)=log4(2x) then f(g(x))= ?
Natali5045456 [20]

Answer:

Step-by-step explanation:

f(x+68)=x

7 0
3 years ago
Match each polynomial expression to is additive inverse
andriy [413]

Answer:

<em>hope</em><em> </em><em>y</em><em>o</em><em>u</em><em> </em><em>get</em><em> </em><em>it</em><em> </em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em>

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3 years ago
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