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fomenos
3 years ago
10

51. Jonathan is selling vintage albums to a rare music

Mathematics
1 answer:
Doss [256]3 years ago
6 0
The answer is D.$27.50
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Pls help me almost due
iVinArrow [24]

Answer: disagree its backwards

Step-by-step explanation: the x intercept always comes first so its actually (-4,2)

6 0
3 years ago
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50 pts + Brainliest Please help <a href="/cdn-cgi/l/email-protection" class="__cf_email__" data-cfemail="462b2306">[email&#160;p
LiRa [457]
The radius of the cylinder's base is 8, so the volume of the cylinder is \pi8^218\approx3617.28 (using the approximation of \pi\approx3.14).

The sphere has radius 6, so the volume of the sphere is \dfrac43\pi6^3\approx904.32.

The volume of the shaded region is the difference between the two: 3617.28 - 904.32 = 2712.96. Rounded to the nearest integer gives an answer of 2713.
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3 years ago
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Write the expression for the Area of the polygon BORT MO 6 A= O A = 6m + mp O A = mp + 1/2(6m) O A = mp + 6p
anyanavicka [17]

We are asked to determine the area of the given figure. To do that we will divide the figure into a square and a triangle. The area of the square is the product of its dimension, therefore, the area is:

A_{sq}=mp

The area of the triangle is given by the following formula:

A_t=\frac{bh}{2}

Where "b" is the base and "h" is its height. Replacing the values:

A_t=\frac{(6)(m)}{2}=\frac{1}{2}6m

The total area is the sum of both areas:

A=A_{sq}+A_t

replacing the areas:

A=mp+\frac{1}{2}6m

7 0
1 year ago
Which dot plot three TVs in two houses
Bogdan [553]

Answer:

A

Step-by-step explanation:

6 0
2 years ago
The area of a triangular block is 81 square inches. If the base of the triangle is twice the height, how long are the base and t
Gre4nikov [31]

Answer:

18 inches and 9 inches

Step-by-step explanation:

Given, The base of a triangle is twice of the height.

Area = 81 sq inches

Let, Base (b) = 2x

Height (h) = x

Area of the triangle = \frac{1}{2}bh

\frac{1}{2}bh = 81

or, x^{2} = 8

Base = 2×9 inches = 18 inches

Height = 9 inches

5 0
2 years ago
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