Intermediate Value Theorem: Suppose that f(x) is an arbitrary, continuous function on an interval [a,b] . If there exists a value L between f(a) and f(b) , then there exists a corresponding value c∈(a,b) , such that f(c)=L
f(x)=x3+4x−1
f(0)=−1f(1)=4
Since the function changes sign in the interval (0,1) , hence there exists a c∈(0,1) such that f(c)=0
you can use formular method or factorisation but formular method is easy and convinient
Answer:
its A C D
Step-by-step explanation:
did it on edg and got it right
Answer:
all work is pictured and shown
The answer is definitely 60%
