C=0.184 mol/L
n=0.113 mol
n=CV
V=n/C
V=0.113/0.184=0.614 L = 614 mL
You only can calculate the empirical formula with that information. I can not guarantee the empirical formula is going to be the same than the molecular formula. To be able to calculate the molecular formula you need the molecular mass or other information.
58.8/12= C = 4.9 => 4.9/1.96 = 2.5 => 2.5*2= 5
9.8/1= H = 9.8 => 9.8/1.96 = 5 => 5* 2= 10
31.4/16=O = 1.96 =>1.96/1.96 = 1 => 1*2 =2
empirical formula C5H10O2
Answer:
2060.775 J
Explanation:
From the question given above, we obtained the following data:
Specific heat capacity (C) = 0.129 J/g°C
Mass (m) = 355 g
Initial temperature (Tᵢ) = 95 °C
Final temperature (Tբ) = 140 °C
Heat (Q) tranfered =?
We can calculate the amount of heat transferred by using the following formula:
Q = mC(Tբ – Tᵢ)
Q = 355 × 0.129 (140 – 95)
Q = 45.795 × 45
Q = 2060.775 J
Thus, 2060.775 J of energy was transferred.