If you sketch a Lewis dot structure of I3-, you'll perceive
that the center I atom formulates two bonds, and also has three non-bonding
pairs of electrons. That's an over-all of five electron pairs - beyond an
octet. Lots of compounds disrupt the octet rule that means, but the first long-row
elements like F can't because the lower elements like iodine can use an obtainable
d-orbital to house the additional pair of electrons (sp3d hybridization), but F
just doesn't have a d-orbital that it can use.
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Answer:
−2399.33 kJ
Explanation:
If NH₄NO₃ reacts with fuel oil to give a ΔH of -7198 for every 3 moles of NH₄NO₃
What is the enthalpy change for 1.0 mole of NH₄NO₃ in this reaction
∴ For every 1 mole, we will have 
of the total enthaply of the 3 moles
so, to determine the 1 mole; we have:
= −2399.33 kJ
∴ the enthalpy change for 1.0 mole of NH₄NO₃ in this reaction = −2399.33 kJ
Answer:
T2= 7.3°C
Explanation:
To solve this problem we will use Charles law equation i.e,
V1/T1 = V2/T2
Given data
V1 = 269.7 L
T1 = 6.12 °C
V2= 320.4 L
T2=?
Solution:
Now we will put the values in equation
269.7 L / 6.12°C = 320.4 L / T2
T2= 320.4 L × 6.12°C/ 269.7 L
T2= 1960.85 °C. L /269.7 L
T2= 7.3°C
Answer:
Explanation:
The two green substances are not the same. Most of their properties are different, except some are alike. Since not all of their properties are matching, they are not the same substance.
I am not sure if this is what you were looking for, but if it is then I am happy to help.
