X=width of a coccer pitch
2x-20=length of a soccer pitch
Area (rectangule)=length x width
We suggest this equation:
x(2x-20)=6000
2x²-20x=6000
2x²-20x-6000=0
x²-10x-3000=0
We solve this quadratic equation:
x=[10⁺₋√(100-4*1*-3000)]/2=[10⁺₋√(100+12000)]/2=
=(10⁺₋110)/2
we have two solutions:
x₁=(10-110)/2=-50, invalid solution.
x₂=(10+110)/2=60
x=60
2x-20=2(60)-20=120-20=100
Solution: the length is 100 m, and the width is 60 m.
To check:
Area=100 m*60 m=6000 m²
The twice of width is =2(60 m)=120 m,
20 m less than twice its width is: 120 m-20 m=100 m=the length.
Answer:
130
Step-by-step explanation:
its basically the same thing
Multiply both sides by 6
(b-4)/6*6= b-4
b/2*6= 3b
Rewrite the equation
b-4= 3b
Subtract b from both sides
-4=2b
Divide both sides by 2
-2=b
Final answer: b=-2
Answer:
A
Step-by-step explanation:
-x + 2y = 8
5x + 2y = -4
+ x. -2y. -8
6x = -12
÷6. ÷6
x = -2
5(-2) + 2y = -4
-10 + 2y = -4
+10. +10
2y = 6
÷2. ÷2
y = 3
Answer:
Therefore the angle that the line through the given pair of points makes with the positive direction of the x-axis is 45°.
Step-by-step explanation:
Given:
Let
A(x₁ , y₁) = (1 , 4) and
B( x₂ , y₂ ) = (-1 , 2)
To Find:
θ = ?
Solution:
Slope of a line when two points are given is given bt
Substituting the values we get
Also Slope of line when angle ' θ ' is given as
Substituting Slope = 1 we get
We Know That for angle 45°,
tan 45 = 1
Therefore
Therefore the angle that the line through the given pair of points makes with the positive direction of the x-axis is 45°.
