The question requires that we have to state the hypothesis:
null hypothesis;H0: u1 < u2, the alternate hypothesis;H1: u1 > u2. The one tail test is what is to be used.
<h3>A.
How to state the hypothesis</h3>
H0: u1 < u2
H1: u1 > u2
The one tail test statistic is what is to be used here
<h3>B.
standard error </h3>

= 1.49
The df = 17 + 15 - 2
= 30
test statistic = 18.9 - 17.4 / 1.49
= 1.007
We have the critical value on excel as T.INV(0.9,30)
= 1.310
E. At 0.1, we can conclude that t-value (1.007) does not lies in the rejection area. We fail to reject the null hypothesis. Hence we conclude that the mean vacation with the unlimited plan is greater.
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Answer:
B; 15 sides
Step-by-step explanation:
Percent change = change/original * 100
(2.65 - 2.30)/ 2.65 * 100
.35/2.65 * 100
13.2 % decrease
-13.2% if you need to write is as a negative
Answer:
1 3/15
1 5/15
Step-by-step explanation:
Let's simplify step-by-step To understand :)
3x2−7x−(x2+3x−9)
Distribute the Negative Sign:
=3x2−7x+−1(x2+3x−9)
=3x2+−7x+−1x2+−1(3x)+(−1)(−9)
=3x2+−7x+−x2+−3x+9
Combine Like Terms:)
=3x2+−7x+−x2+−3x+9
=(3x2+−x2)+(−7x+−3x)+(9)
=2x2+−10x+9
Answer :)
=2x2−10x+9
HOPE THIS HELPS