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yKpoI14uk [10]
4 years ago
15

Where is the answer to the expression 4 − 8 located on a horizontal number line?

Mathematics
1 answer:
Usimov [2.4K]4 years ago
6 0
-4. Hopefully this helps.
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The diagonal of a rectangle is 15cm and the perimeter is 38cm . what is the area?​
babymother [125]

Answer:

570cm squared

Step-by-step explanation:

Multiply 38 by 15.

6 0
3 years ago
Solve the equation. Show the process, not just an answer. 6.EE.7
Natalka [10]

Isolate the variable, note the equal sign, what you do to one side, you do to the other.

1) 4k = 24

Isolate the variable, k. Divide 4 from both sides of the equation:

(4k)/4 = (24)/4

k = 24/4

k = 6

2) 34 + h = 60

Isolate the variable, h. Subtract 34 from both sides of the equation:

34 (-34) + h = 60 (-34)

h = 60 - 34

h = 26

3) 1/5x = 30

Isolate the variable, x. Multiply 5 to both sides of the equation:

(5) * (1/5)x = (30) * (5)

x = 30 * 5

x = 150

4) m - 42 = 85

Isolate the variable, m. Add 42 to both sides of the equation:

m- 42 (+42) = 85 (+42)

m = 85 + 42

m = 127

~

6 0
3 years ago
The town of madison has a population of 25,000. The population is increasing by a factor of 1.12 each year. Write a function tha
GaryK [48]
<h3>The population P(t) at the end of year t is   P(t)   = 25,000 \times (1.12)^t</h3>

Step-by-step explanation:

The initial population of town of Madison = 25,000

The rate at which the population is increasing = 1.12 times

So, the increase in population first year  :

( the initial population)  x (1.12)^1  = 1.12 x ( 25,000)  

= 28,000

So, the population at the end of first year = 28,000

Similarly, the increase in population second year  :

( the initial population)  x (1.12)²  =  ( 25,000)   x (1.12)²

= 31,360

So, the population at the end of second year =31,360

Now, to calculate the population in t years from now:

The population P(t) at the end of year t is

P(t)   = 25,000 \times (1.12)^t

5 0
3 years ago
Scores on the final in a statistics class are as follows.
IgorLugansk [536]

Answer:

Kindly check explanation

Step-by-step explanation:

Calculate the 25th, 50th, and 75th percentiles.

b. Calculate the interquartile range.

c. Construct a boxplot. Are there any outliers?

Reordered data:

25, 40, 52, 55, 60, 70, 70, 72, 74, 75, 75, 80, 80, 85, 85, 86, 87, 90, 92, 99

25 th percentile :

1/4 (n + 1)th, tetm

n = 20

1/4(21) = 5.25th term

(5 + 6) th term / 2

= 65

50th percentile :

1/2 (n + 1)th, tetm

n = 20

1/2(21) = 10.5th term

(10 + 11) th term / 2

= 75

75th percentile:

3/4 (n + 1)th, tetm

n = 20

3/4(21) = 15.75th term

(15 + 16) th term / 2

= 85.5

Interquartile range :

Q3 - Q1

75th percentile - 25th percentile

85.5 - 65

= 20.5

25 is an Outlier

7 0
3 years ago
19x^2+15x+12 divided by x-2
Serggg [28]

Answer:

Step-by-step explanation:

8 0
3 years ago
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