Answer:
570cm squared
Step-by-step explanation:
Multiply 38 by 15.
Isolate the variable, note the equal sign, what you do to one side, you do to the other.
1) 4k = 24
Isolate the variable, k. Divide 4 from both sides of the equation:
(4k)/4 = (24)/4
k = 24/4
k = 6
2) 34 + h = 60
Isolate the variable, h. Subtract 34 from both sides of the equation:
34 (-34) + h = 60 (-34)
h = 60 - 34
h = 26
3) 1/5x = 30
Isolate the variable, x. Multiply 5 to both sides of the equation:
(5) * (1/5)x = (30) * (5)
x = 30 * 5
x = 150
4) m - 42 = 85
Isolate the variable, m. Add 42 to both sides of the equation:
m- 42 (+42) = 85 (+42)
m = 85 + 42
m = 127
~
<h3>
The population P(t) at the end of year t is 
</h3>
Step-by-step explanation:
The initial population of town of Madison = 25,000
The rate at which the population is increasing = 1.12 times
So, the increase in population first year :
( the initial population) x
= 1.12 x ( 25,000)
= 28,000
So, the population at the end of first year = 28,000
Similarly, the increase in population second year :
( the initial population) x (1.12)² = ( 25,000) x (1.12)²
= 31,360
So, the population at the end of second year =31,360
Now, to calculate the population in t years from now:
The population P(t) at the end of year t is

Answer:
Kindly check explanation
Step-by-step explanation:
Calculate the 25th, 50th, and 75th percentiles.
b. Calculate the interquartile range.
c. Construct a boxplot. Are there any outliers?
Reordered data:
25, 40, 52, 55, 60, 70, 70, 72, 74, 75, 75, 80, 80, 85, 85, 86, 87, 90, 92, 99
25 th percentile :
1/4 (n + 1)th, tetm
n = 20
1/4(21) = 5.25th term
(5 + 6) th term / 2
= 65
50th percentile :
1/2 (n + 1)th, tetm
n = 20
1/2(21) = 10.5th term
(10 + 11) th term / 2
= 75
75th percentile:
3/4 (n + 1)th, tetm
n = 20
3/4(21) = 15.75th term
(15 + 16) th term / 2
= 85.5
Interquartile range :
Q3 - Q1
75th percentile - 25th percentile
85.5 - 65
= 20.5
25 is an Outlier
Answer:
Step-by-step explanation: