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2 years ago

Can someone please help me with this math question?

Mathematics

1 answer:

otez555 [7]2 years ago

5 0

9514 1404 393

Answer:

D. 0, 1, or 2 solutions

Step-by-step explanation:

The line represented by g(x) may intersect the parabola represented by f(x) in 0, 1, or 2 places, as illustrated in the attachment. The curves are different shapes, so cannot overlap to give infinite solutions.

The system may have 0, 1, or 2 solutions.

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Please help! I can't figure this out!

ipn [44]

Answer:

1 & -1

Step-by-step explanation:

f(x) = g(x)

Find the inputs for which outputs are equal

Both outputs are 1 when x = -1

Both outputs are -7 when x = 1

6 0

3 years ago

Elena has $240 in the bank. She withdraws $15 each week to pay for her piano lessons. How many lessons can she afford with her s

Ivahew [28]

16 lesson. The equation is 240÷15=16
And like I said 240÷15 is 16
So here I hope it helped You
~jZ

6 0

3 years ago

Maggie graphed the image of a 90 counterclockwise rotation about vertex A of . Coordinates B and C of are (2, 6) and (4, 3) and

Lemur [1.5K]

Answer:

A(2,2)

Step-by-step explanation:

Let the vertex A has coordinates $(x_A,y_A)$

Vectors AB and AB' are perpendicular, then

$\overrightarrow {AB}=(2-x_A,6-y_A)\\ \\\overrightarrow {AB'}=(-2-x_A,2-y_A)\\ \\\overrightarrow {AB}\perp\overrightarrow {AB'}\Rightarrow \overrightarrow {AB}\cdot \overrightarrow {AB'}=0\Rightarrow (2-x_A)(-2-x_A)+(6-y_A)(2-y_A)=0$

Vectors AC and AC' are perpendicular, then

$\overrightarrow {AC}=(4-x_A,3-y_A)\\ \\\overrightarrow {AC'}=(1-x_A,4-y_A)\\ \\\overrightarrow {AC}\perp\overrightarrow {AC'}\Rightarrow \overrightarrow {AC}\cdot \overrightarrow {AC'}=0\Rightarrow (4-x_A)(1-x_A)+(3-y_A)(4-y_A)=0$

Now, solve the system of two equations:

$\left\{\begin{array}{l}(2-x_A)(-2-x_A)+(6-y_A)(2-y_A)=0\\ \\(4-x_A)(1-x_A)+(3-y_A)(4-y_A)=0\end{array}\right.\\ \\\left\{\begin{array}{l}-4-2x_A+2x_A+x_A^2+12-6y_A-2y_A+y^2_A=0\\ \\4-4x_A-x_A+x_A^2+12-3y_A-4y_A+y_A^2=0\end{array}\right.\\ \\\left\{\begin{array}{l}x_A^2+y_A^2-8y_A+8=0\\ \\x_A^2+y_A^2-5x_A-7y_A+16=0\end{array}\right.$

Subtract these two equations:

$5x_A-y_A-8=0\Rightarrow y_A=5x_A-8$

Substitute it into the first equation:

$x_A^2+(5x_A-8)^2-8(5x_A-8)+8=0\\ \\x_A^2+25x_A^2-80x_A+64-40x_A+64+8=0\\ \\26x_A^2-120x_A+136=0\\ \\13x_A^2-60x_A+68=0\\ \\D=(-60)^2-4\cdot 13\cdot 68=3600-3536=64\\ \\x_{A_{1,2}}=\dfrac{60\pm8}{2\cdot 13}=\dfrac{34}{13},2$

Then

$y_{A_{1,2}}=5\cdot \dfrac{34}{13}-8 \text{ or } 5\cdot 2-8\\ \\=\dfrac{66}{13}\text{ or } 2$

Rotation by 90° counterclockwise about A(2,2) gives image points B' and C' (see attached diagram)

8 0

2 years ago

A lawn sprinkler sprays water 25 feet and moves back and forth through an angle of 150°. Which of the following is the best esti

11Alexandr11 [23.1K]

$\pi25 ^{2} \times \frac{150}{360}$
Explanation:
Area is pi×r^2 and you times it by the fraction of the circle you have as its not a full circle.

5 0

3 years ago

Mrs. Cerra planted 4 ⅞ acres of wheat and 1 ⅝ acres of corn. How much more wheat did she plant than corn?

alukav5142 [94]

We can subtract the acres of corn from the acres of wheat.
$4 \frac{7}{8} - 1 \frac{5}{8} = 3 \frac{2}{8} = 3 \frac{1}{4}$
She planted 3 1/4 more acres of wheat than corn.

3 0

2 years ago