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hammer [34]
3 years ago
12

Determine the slope of the line that passes through the points (8,0) and (-3, 9).

Mathematics
1 answer:
Naddik [55]3 years ago
8 0

Answer: 9/11

Step-by-step explanation: (8,0) (-3, 9). Subtract x values, subtract y values. This is known as delta x and delta y. Slope is rise/run. When you subtract the two points, you are finding the different between them. You're able to plug these x values and y values into an equation and get the correct answer. If you substitute x in, you get y. If you substitute y in, you get x (if you simplify it to get x on one side). So, the change is y is on the top, and change in x is on the bottom. 9 is divided by 11. This is the slope. You can plot this point by rising 9 and running (x axis) 11.

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Factor the binomial using its GCF: 10x-15x^4
Igoryamba

Answer:

5x(2 - 3x³)

Step-by-step explanation:

10x-15x^4

The GCF( Greatest Common Factor) of 10x-15x^4 is 5x

Solve:

10x/5x = 2

-15^4/5x = -3x³

Final answer is

5x(2 - 3x³)

                         <u>Check</u>

5x(2 - 3x³)

distribute

5x(2) + 5x(-3x³)

10x - 15x^4

4 0
4 years ago
Read 2 more answers
Evaluate 5x-7 when x=2
Reptile [31]

Answer:

the answer is 3since x is 2 so it becomes 5times 2 minus 7 equals to 3

4 0
1 year ago
Two triangular roofs are similar. The ratio of the corresponding sides of these roofs is 2:3. If the altitude of the smaller roo
schepotkina [342]

Answer:  6.75 feet

Step-by-step explanation:

Since, the ratio of the side of the similar triangle = 2 : 3

Thus, by the property of similar triangle,

The ratio of the altitudes of the triangle = 2 : 3

Let the altitude of smaller triangle = 2 x

And, the altitude of larger triangle = 3 x

Where x is any number.

According to the question,

2 x = 4.5

x = 2.25

Therefore, the altitude of larger triangle = 3 × 2.25 = 6.75 feet

5 0
3 years ago
Two mathematical questions attached below.
BartSMP [9]

Answer:

See below

Step-by-step explanation:

9.( {m}^{3}  {n}^{5} )^{ \frac{1}{4} }   \\   =  m^{\frac{3}{4}}n^{\frac{5}{4}}\\  \\ 10. \sqrt[5]{ \sqrt[4]{x} }  \\  =  \sqrt[5]{ {x}^{ \frac{1}{4} } }  \\  =  {( {x}^{ \frac{1}{4} } )}^{ \frac{1}{5} }  \\   =  {x}^{ \frac{1}{4}  \times  \frac{1}{5} }  \\  =  {x}^{ \frac{1}{20} }  \\  \\ \sqrt[5]{ \sqrt[3]{ {a}^{2} } }  \\  =  \sqrt[5]{ {a}^{ \frac{2}{3} } }  \\  =  {( {a}^{ \frac{2}{3} } )}^{ \frac{1}{5} }  \\   =  {a}^{ \frac{2}{3}  \times  \frac{1}{5} }  \\  =  {a}^{ \frac{2}{15} }

4 0
3 years ago
There are 10 multiple choice questions in an examination. first 4 have 5 choices each and remaining have 4 choices each. how man
stira [4]

2560000 sequences of answers are possible.

<em><u>Explanation</u></em>

Total number of questions = 10

First 4 questions have 5 choices each and remaining (10-4)= 6 questions have 4 choices each.

So, the possible sequences of answers for first 4 questions = 5^4 = 625

and the possible sequences of answers for remaining 6 questions = 4^6=4096

Thus, the total possible number of sequences of answers = (625 × 4096) = 2560000

5 0
3 years ago
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