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Alex73 [517]
3 years ago
9

There are 10 multiple choice questions in an examination. first 4 have 5 choices each and remaining have 4 choices each. how man

y sequences of answers are possible?
Mathematics
2 answers:
maksim [4K]3 years ago
8 0

Answer:


Step-by-step explanation:


stira [4]3 years ago
5 0

2560000 sequences of answers are possible.

<em><u>Explanation</u></em>

Total number of questions = 10

First 4 questions have 5 choices each and remaining (10-4)= 6 questions have 4 choices each.

So, the possible sequences of answers for first 4 questions = 5^4 = 625

and the possible sequences of answers for remaining 6 questions = 4^6=4096

Thus, the total possible number of sequences of answers = (625 × 4096) = 2560000

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I need help!!! Please
Shalnov [3]

Answer:

I know this is not exactly what your looking for but if you make a line and put all the points from 4+3i to 6-2i then you can find the distance between them.

Step-by-step explanation:

I'm so sorry that I don't really know the answer

Pls forgive me

5 0
3 years ago
Use the given information to solve the triangle for A = 150°, b = 4.8, a = 9.4
ELEN [110]
Well you can start by drawing a triangle with the information 

the size of angle B can be found using the Law of Sine

\frac{sin(150)}{9.4)}  =  \frac{sin(B)}{4.8}

the size of angle C can be found using angle sum of a triangle. 

The length of side c can be found using the Law of Cosines

c^2 = 4.8^2 + 9.4^2 - 2 \times4.8\times9.4\times  cos(C)

hope it helps
7 0
3 years ago
Can you solve some of these? Or all, whichever one you might know. Also explain please.
Rina8888 [55]
Here's number 5. If you need more explanation just let me know.

8 0
3 years ago
Y'all is so nice too help me I really appreciate it help me thanks<br> plz i need help
butalik [34]
You can multiply 2/3 by 2/2 to get 4/6. This means that x=4!!!

Hope this helps :)
8 0
3 years ago
Can someone help me with this and show their work and how they found the answer?
Semenov [28]

Answer:

2kg

Step-by-step explanation:

Let the sum of the other 2 bricks be R. Given that the heaviest brick weighs 2/3 times as much as the other 2 bricks in total, then the weight of the heaviest brick H in terms of the weight of the other 2 will be

H = 2/3 * R

= 2R/3

Given that the 3 bricks weigh 5kg in total then,

2R/3 + R = 5

Multiply through the equation by 3

2R + 3R = 15

5R = 15

Divide both sides by 5

R = 15/5

= 3

The weight of the heaviest brick is 2R/3. Since R = 3, the heaviest block weighs

= 2 * 3/3

= 2kg

4 0
3 years ago
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