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Alex73 [517]
3 years ago
9

There are 10 multiple choice questions in an examination. first 4 have 5 choices each and remaining have 4 choices each. how man

y sequences of answers are possible?
Mathematics
2 answers:
maksim [4K]3 years ago
8 0

Answer:


Step-by-step explanation:


stira [4]3 years ago
5 0

2560000 sequences of answers are possible.

<em><u>Explanation</u></em>

Total number of questions = 10

First 4 questions have 5 choices each and remaining (10-4)= 6 questions have 4 choices each.

So, the possible sequences of answers for first 4 questions = 5^4 = 625

and the possible sequences of answers for remaining 6 questions = 4^6=4096

Thus, the total possible number of sequences of answers = (625 × 4096) = 2560000

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Rina8888 [55]

Answer:

C. cos 20/29

Step-by-step explanation:

Cosine is adjacent over hypotenuse, like SohCahToa. Therefore, 20 is the adjacent side and 29 is the hypotenuse (hypotenuse is always the longest side).

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3 years ago
2x=10<br>find the value of x​
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see below (I hope this helps!)

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43. The sum of interior angles in a triangle is 180°, therefore, x = 180 - (75 + 64) = 41°.

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