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gayaneshka [121]
3 years ago
11

what are the squares from 1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20 answer when multiplied by itself​

Mathematics
2 answers:
miss Akunina [59]3 years ago
8 0

Step-by-step explanation:

Is this the answer you want? If nope inform me.i hope you just ignore my handwriting ☺️

nordsb [41]3 years ago
7 0

Answer:

I hope it helps :)

Step-by-step explanation:

{1}^{2}  = 1 \times 1  = 1\\  {2}^{2}  = 2 \times 2  = 4\\  {3}^{2}  =3  \times 3  = 9\\  {4}^{2}  = 4 \times 4 = 16 \\

{5}^{2}   = 5 \times 5 = 25 \\  {6}^{2}  = 6 \times 6 = 36 \\  {7}^{2}  = 7 \times 7  = 49\\  {8}^{2}  = 8 \times 8 = 64

{9}^{2}  = 9 \times 9 = 81 \\  {10}^{2}  = 10 \times 10 = 100 \\  {11}^{2}  = 11 \times 11 = 121 \\  { {12}^{2} } = 12 \times 12 = 144

{13}^{2}  = 13 \times 13 = 169 \\  {14}^{2}  = 14 \times 14 = 196 \\  {15}^{2}  = 15 \times 15 = 225 \\  {16}^{2}  = 16 \times 16 = 256

{17}^{2}  = 17 \times 17 = 289 \\  {18}^{2}  = 18 \times 18 = 324 \\  {19}^{2}  = 19 \times 19 = 361 \\  {20}^{2}  = 20 \times 20 = 400

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IgorLugansk [536]

Answer:

b) Then z(s) is in the rejection region for H₀. We reject H₀. The p-value is smaller than α/2

c)CI 95 %  =  ( 0.00002 ;  0.09998)

Step-by-step explanation: In both cases, the size of the samples are big enough to make use of the approximation of normality of the difference of the proportions.

Recent Sample

Sample size    n₁  =  1000

Number of events of people with financial fitness more than fair

x₁  =  410

p₁ =  410/ 1000  =  0.4     then q₁ = 1 - p₁    q₁ =  1 -  0.4    q₁  = 0.6

Sample a year ago

Sample size    n₂ =  1200

Number of events of people with financial fitness more than fair

x₂  =  420

p₂  =  420/1200     p₂ = 0.35   q₂  =  1 - p₂    q₂  = 1 - 0.35   q₂ = 0.65

Test Hypothesis

Null Hypothesis                                  H₀              p₁  =  p₂

Alternative Hypothesis                      Hₐ              p₁  ≠  p₂

CI  95 % then significance level  α  =  5%   α  = 0.05    α/2  = 0.025

To calculate p-value:

SE  =  √ (p₁*q₁)/n₁  +  (p₂*q₂)/n₂

SE  =  √ 0.4*0.6/1000 +  0.65*0.35/1200

SE  =  √ 0.00024 + 0.000189

SE = 0.021

z(s) =  ( p₁ - p₂ ) / SE

z(s) = ( 0.4 - 0.35 )/0.021

z(s) = 0.05/ 0.021

z(s) =  2.38

We find p-value from z-table to be   p-value = 0.00842

Comparing

p-value with  α/2   = 0.025

α/2 >  p-value  

Then z(s) is in the rejection region for H₀. We reject H₀

CI 95 %  =  ( p₁  -  p₂ )  ±  2.38*SE

CI 95 %  =  ( 0.05 ± 2.38*0.021 )

CI 95 %  =  ( 0.05 ± 0.04998)

CI 95 %  =  ( 0.00002 ;  0.09998)

CI 95 % does not contain the 0 value affirming what the hypothesis Test already demonstrate

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

three-fourths also means 3 out of 4. This can be shown as a fraction as 3/4

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