Answer:
The degrees of freedom is 11.
The proportion in a t-distribution less than -1.4 is 0.095.
Step-by-step explanation:
The complete question is:
Use a t-distribution to answer this question. Assume the samples are random samples from distributions that are reasonably normally distributed, and that a t-statistic will be used for inference about the difference in sample means. State the degrees of freedom used. Find the proportion in a t-distribution less than -1.4 if the samples have sizes 1 = 12 and n 2 = 12 . Enter the exact answer for the degrees of freedom and round your answer for the area to three decimal places. degrees of freedom = Enter your answer; degrees of freedom proportion = Enter your answer; proportion
Solution:
The information provided is:
Compute the degrees of freedom as follows:
Thus, the degrees of freedom is 11.
Compute the proportion in a t-distribution less than -1.4 as follows:
*Use a <em>t</em>-table.
Thus, the proportion in a t-distribution less than -1.4 is 0.095.
Answer:
Step-by-step explanation:
1) (x-3),(x-8)
2) 3x^3+3x^2=27x
3
(
x
3^3+
x
^2
−
9
x
−
9
)
3
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x
^2
(
x
+
1
)
−
9
(
x
+
1
)
)
3
(
(
x
+
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x
^2
−
9
)
)
3
(
(
x
+
1
)
(
x
^2
−
3
^2
)
)
3
(
x
+
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(
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3
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(
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3
)
Answer:
Check the explanation
Step-by-step explanation:
Y = 11.5 + 4.5*X1 -2.5*X2 +0.7*X3+1.6*X4 -2.4*X5 -2.8*X6
FOR JANE
X1 =1 , X2 =1 , X3 =5 , X4 =0 ,X5=0, X6=1
SO,
Y =11.5+(4.5*1)-(2.5*1)+(0.7*5)+0+0-(2.8*1)
= 14.2
..........................
FOR Sophie
X1 =1 , X2 =1 , X3 =10 , X4 =1 ,X5=0, X6=0
so,
Y =11.5+(4.5*1)-(2.5*1)+(0.7*10)+ (1.6*1)+0+0
= 22.1