Answer:
3/12 and 5/x
12 times 5 is 60 so 3 times 20 shall be 60
3/12 = 5/20
:)
Answer:
In disguise right arrow In Standard Form a, b and c
x2 = 3x − 1 Move all terms to left hand side x2 − 3x + 1 = 0 a=1, b=−3, c=1
2(w2 − 2w) = 5 Expand (undo the brackets),
and move 5 to left 2w2 − 4w − 5 = 0 a=2, b=−4, c=−5
z(z−1) = 3 Expand, and move 3 to left z2 − z − 3 = 0 a=1, b=−1, c=−3
Step-by-step explanation:
sorry it took so long
Answer:
Now, 3x 2+x+5⩾0
This is because b² −4ac=1−4×5×3
=−59 (roots are imaginary)
3x²+x+5=(x−3)² =x²+9−6x and x−3⩾0
2x²+7x−4=0
2x²+8x−x−4=0
2x(x+4)−1(x+4)=0
(2x−1)(x+4)=0
x= 1/2 and−4 but x≥3
∴ No solution.
lol hehehe
A B
D C
vectors
AB = DC
AB (-2-7 ; 3-1) => AB (-9 ; 2)
DC (1-x : -7-y)
1 - x = -9 => x = 10
-7-y = 2 => y = -9
D(10 ; -9)
