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Volgvan
3 years ago
13

What is the least common multiple of all numbers 1-12

Mathematics
1 answer:
Otrada [13]3 years ago
8 0
The LCM is: <span>2,7,7,2,0.</span>
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Graph the image of this figure after a dilation with a scale factor of 2 centered at (2, 2).
Maru [420]

Answer:

(-6,6), (0,12), (4,8)

Step-by-step explanation:

To dilate an object, we need to multiply the x and y values by the given scale factor.

In this case the scale factor is 2 --> 2(x, y)

Before-> After dilation

2(-3,3) = (-6,6)

2(0,6) = (0,12)

2(2,4) = (4,8)

Please leave a 'thanks' if this helps!

6 0
3 years ago
(8-5/2-2)-4<br> =?<br><br> Please helping me!!!
frez [133]

Answer: Hope This Helps!

Step-by-step explanation:

Simplify the expression.

Exact Form:

87/40

Decimal Form:

2.175

Mixed Number Form:

2 7/40

5 0
2 years ago
Two mathematical questions attached below.
BartSMP [9]

Answer:

See below

Step-by-step explanation:

9.( {m}^{3}  {n}^{5} )^{ \frac{1}{4} }   \\   =  m^{\frac{3}{4}}n^{\frac{5}{4}}\\  \\ 10. \sqrt[5]{ \sqrt[4]{x} }  \\  =  \sqrt[5]{ {x}^{ \frac{1}{4} } }  \\  =  {( {x}^{ \frac{1}{4} } )}^{ \frac{1}{5} }  \\   =  {x}^{ \frac{1}{4}  \times  \frac{1}{5} }  \\  =  {x}^{ \frac{1}{20} }  \\  \\ \sqrt[5]{ \sqrt[3]{ {a}^{2} } }  \\  =  \sqrt[5]{ {a}^{ \frac{2}{3} } }  \\  =  {( {a}^{ \frac{2}{3} } )}^{ \frac{1}{5} }  \\   =  {a}^{ \frac{2}{3}  \times  \frac{1}{5} }  \\  =  {a}^{ \frac{2}{15} }

4 0
2 years ago
A reactangle has a perimeter 182 in and length 52 in . what is the width ?
Misha Larkins [42]
The Width Should Be 130 Because If You Subtract 182-52 You Get 130
4 0
3 years ago
Read 2 more answers
Solve ry + s = tx - m for y. Explain each step in your solution.
sergeinik [125]

y = (t x - m -s)/r

Step-by-step explanation:

Step 1 :

Given,

r y + s = t x - m

=> r y = t x - m -s

=>  y = (t x - m -s)/r

Step 2 :

A) r can take any values except 0.

This is because when r = 0, the denominator becomes 0 and division by 0 is undefined

The limitation for r is r should not be equal to 0

The other variables can take any value. Hence the other variables do not have any limitation

7 0
3 years ago
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