Answer:
a. P(x = 0 | λ = 1.2) = 0.301
b. P(x ≥ 8 | λ = 1.2) = 0.000
c. P(x > 5 | λ = 1.2) = 0.002
Step-by-step explanation:
If the number of defects per carton is Poisson distributed, with parameter 1.2 pens/carton, we can model the probability of k defects as:
a. What is the probability of selecting a carton and finding no defective pens?
This happens for k=0, so the probability is:
b. What is the probability of finding eight or more defective pens in a carton?
This can be calculated as one minus the probablity of having 7 or less defective pens.
c. Suppose a purchaser of these pens will quit buying from the company if a carton contains more than five defective pens. What is the probability that a carton contains more than five defective pens?
We can calculate this as we did the previous question, but for k=5.
Answer:
13.400
Step-by-step explanation:
Lets start with 416 First go to the 6 and since its over 4 we can automatically know that it makes the 1 in 416 to a 2 and the 2 cannot go up any higher so we make everything else below 4 a zero.
Answer:
11.7
Step-by-step explanation:
It would end up being 2 dollars and 45 cents
The required value of y is 2645 / 77 when x = 77.
Step-by-step explanation:
1. Let's check the information given to answer:
if y varies inversely as x, and y = 23 when x = 115. Find y when x=77
2. What is y when x = 77?
As the statement "y varies inversely as x" translates into y = k/x
If we let y = 23 and x = 115, the constant of variation becomes
23 = k ÷ 115
k = 23 × 115
k = 2645
Thus the specification equation is y = 2645 ÷ x . Now, letting x = 77, we obtain
y = 2645 ÷ x
y = 2645 ÷ 77
<u>So, The required value of y = 2645 / 77 when x = 77</u>
<u></u>
<u>#learnwithBrainly</u>