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3 years ago

The P.E. class has 21 jump ropes. If each jump rope is 1.524 meters long, how long are the jump ropes altogether?

Mathematics

1 answer:

Taya2010 [7]3 years ago

3 0

Answer:

32.4

Step-by-step explanation:

Just multiply 21 x 1.524 and you get 32.004 as your answer.

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If you roll six sided dice what are the odds of rolling doubles

Ludmilka [50]

Answer: 16.7%

There are 6 ways we can roll doubles out of a possible 36 rolls (6 x 6), for a probability of 6/36, or 1/6, on any roll of two fair dice. So you have a 16.7% probability of rolling doubles with 2 fair six-sided dice.

Second Answer : 6/36

Out of the 6^2 = 36 outcomes, there is only 6 that are doubles (double 1,double 2,… double 6). Therefore the probability is 6/36 i 1/6.

5 0

3 years ago

Alinethatincludesthepoint(2, 7)has slope of 5 . what isitsequationin slope -intercept form

Vesna [10]

10? Im not sure though my friend just told me it was 10

8 0

3 years ago

Can someone help me find the equivalent expressions to the picture below? I’m having trouble

miss Akunina [59]

Answer:

Options (1), (2), (3) and (7)

Step-by-step explanation:

Given expression is $\frac{\sqrt[3]{8^{\frac{1}{3}}\times 3} }{3\times2^{\frac{1}{9}}}$ .

Now we will solve this expression with the help of law of exponents.

$\frac{\sqrt[3]{8^{\frac{1}{3}}\times 3} }{3\times2^{\frac{1}{9}}}=\frac{\sqrt[3]{(2^3)^{\frac{1}{3}}\times 3} }{3\times2^{\frac{1}{9}}}$

$=\frac{\sqrt[3]{2\times 3} }{3\times2^{\frac{1}{9}}}$

$=\frac{2^{\frac{1}{3}}\times 3^{\frac{1}{3}}}{3\times 2^{\frac{1}{9}}}$

$=2^{\frac{1}{3}}\times 3^{\frac{1}{3}}\times 2^{-\frac{1}{9}}\times 3^{-1}$

$=2^{\frac{1}{3}-\frac{1}{9}}\times 3^{\frac{1}{3}-1}$

$=2^{\frac{3-1}{9}}\times 3^{\frac{1-3}{3}}$

$=2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }$ [Option 2]

$2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }=(\sqrt[9]{2})^2\times (\sqrt[3]{\frac{1}{3} } )^2$ [Option 1]

$2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }=(\sqrt[9]{2})^2\times (\sqrt[3]{\frac{1}{3} } )^2$

$=(2^2)^{\frac{1}{9}}\times (3^2)^{-\frac{1}{3} }$

$=\sqrt[9]{4}\times \sqrt[3]{\frac{1}{9} }$ [Option 3]

$2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }=(2^2)^{\frac{1}{9}}\times (3^{-2})^{\frac{1}{3} }$

$=\sqrt[9]{2^2}\times \sqrt[3]{3^{-2}}$ [Option 7]

Therefore, Options (1), (2), (3) and (7) are the correct options.

6 0

3 years ago

Ashley has a sprinkler that has several varieties of coverage. The quarter circle sprinkler head sprays water a distance of up t

alukav5142 [94]

Answer:

314 square feet

Step-by-step explanation:

we know that

The area that will be covered by the spray of the quarter-circle sprinkler head, is equal to the area of a quarter circle with radius of 20 feet

The area of a quarter circle is

$A=\frac{1}{4}\pi r^{2}$

we have

$r=20\ ft$

$\pi =3.14$

substitute

$A=\frac{1}{4}(3.14)(20)^{2}=314\ ft^2$

8 0

3 years ago

Given <br> m<br> ∥<br> n<br> m∥n, find the value of x and y.

zlopas [31]

<h2>Answer:</h2><h2>X=41°</h2><h2>Y=41°</h2><h2>Step-by-step explanation:</h2>

<h2>Y= 41° ( vertically opposite angles are equal)</h2><h2>X=Y ( alternate angles are equal)</h2><h2>therefore X = 41°</h2>

5 0

2 years ago